OK. I am looking at solution #2.
I have figured out where to make my page content hidden. (see below)
Now where would I add the "visible" property to bring content back
when user moves mouse off menus or drop-downs.
thanks
itp
PHP Code:
dropit:function(obj, e, dropmenuID)
{
if (this.dropmenuobj!==null) //hide previous menu
this.dropmenuobj.style.visibility="hidden";
this.clearhidemenu();
// **********turn off upper page content here *********
document.getElementById("visibility").style.visibility = "hidden";
// ********************************************
if (this.ie||this.firefox)
{
obj.onmouseout=function()
{cssdropdown.delayhidemenu()
}
this.dropmenuobj=document.getElementById(dropmenuID)
this.dropmenuobj.onmouseover=function() {cssdropdown.clearhidemenu()}
this.dropmenuobj.onmouseout=function(){cssdropdown.dynamichide(e)}
this.dropmenuobj.onclick=function(){cssdropdown.delayhidemenu()}
this.showhide(this.dropmenuobj.style, e, "visible", "hidden")
this.dropmenuobj.x=this.getposOffset(obj, "left")
this.dropmenuobj.y=this.getposOffset(obj, "top")
this.dropmenuobj.style.left=this.dropmenuobj.x-this.clearbrowseredge(obj, "rightedge")+"px"
this.dropmenuobj.style.top=this.dropmenuobj.y-this.clearbrowseredge(obj, "bottomedge")+obj.offsetHeight+1+"px"
}
},
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