Photo Album 2.1 Image date

[pellsonline]

I am using php photo album and it works great.

I am using the autodesc option %d to display date.

This displays the date the image was last modified.

I have modified the getalbumpics.php file to remove hour, minutes and seconds and display mm/dd/yyy



My question is: can I display the date the image was created?

Thank you

[jscheuer1]

If the image has EXIF data which many cameras, software and other devices create automatically and that data contains that information and the EXIF data has been preserved (many image editing programs can strip it to save on bytes), you can use that. See:

http://stackoverflow.com/questions/1...p-exif-read-da

and:

http://www.php.net/manual/en/functio...-read-data.php

If that's not enough info for you to adapt your PHP code to get what you want, let me know. But, as I say, if the EXIF data isn't there or doesn't contain that information, you cannot get it.

Oh, and some image editing programs allow you to create such data if it wasn't originally saved or was stripped. But at that point you have to be able to remember when the image was created or be able to retrieve the info from an original version that might still have it.

[pellsonline]

Thanks John,

My images are all recent digital camera so they should have EXIF data.

I am a novice and really not up on coding. I can usually work it out by trial & error.

This is the original code:

<?
Header("content-type: application/x-javascript");

function returnimages($dirname=".") {
   $pattern="\.(jpg|jpeg|png|gif|bmp)$";
   $files = array();
   $curimage=0;
   if($handle = opendir($dirname)) {
       while(false !== ($file = readdir($handle))){
               if(eregi($pattern, $file)){
         $filedate=date ("M d, Y", filemtime($file));
                 echo "        [$curimage, \"$file\", \"$filedate\"],\n";
                 $curimage++;
               }
       }
       echo "        [\"placeholder\"]\n";
       closedir($handle);
   }
   return($files);
}

$photovar=$_GET['id'];
if (!eregi("^[a-zA-Z0-9_]+$", $photovar)){
    echo "alert(\"Photo Album ID must contain only letters, numbers, or underscore, and cannot start with a number\")";
    die();
}
echo "var $photovar={\n";
echo "    baseurl: \"http://" . $_SERVER["SERVER_NAME"] . dirname($_SERVER['PHP_SELF']) . "/\",\n";
echo "    images: [\n";
returnimages();
echo "    ],\n";
echo "    desc: []\n";
echo "}\n";
?>

I have tried making changes described in the two links you send me but can't figure it out. Can you just point me to the area to change?

Thanks,
Joe

[jscheuer1]

I tried this out in a simplified version and it worked:

<?php
$exif = exif_read_data('PICT0002.JPG');
echo date("m/d/Y", $exif['FileDateTime']);
?>

But I had to enable exif first. That may or may not be an issue with your server. If it is, see:

http://www.rudibela.com/web-developm...xif-extension/

Assuming something like that works, this might be good for the getalbumpics.php file:

<? 
Header("content-type: application/x-javascript"); 

function returnimages($dirname=".") { 
   $pattern="\.(jpg|jpeg|png|gif|bmp)$"; 
   $files = array(); 
   $curimage=0; 
   if($handle = opendir($dirname)) { 
       while(false !== ($file = readdir($handle))){ 
               if(eregi($pattern, $file)){ 
         $filedate=date ("M d, Y", filemtime($file)); 
             $exif = exif_read_data($file);
             if($exif) {echo "        [$curimage, \"$file\", \"" . date("M d, Y", $exif['FileDateTime']) . "\"],\n";} 
                 else {echo "        [$curimage, \"$file\", \"$filedate\"],\n";} 
                 $curimage++; 
               } 
       } 
       echo "        [\"placeholder\"]\n"; 
       closedir($handle); 
   } 
   return($files); 
} 

$photovar=$_GET['id']; 
if (!eregi("^[a-zA-Z0-9_]+$", $photovar)){ 
    echo "alert(\"Photo Album ID must contain only letters, numbers, or underscore, and cannot start with a number\")"; 
    die(); 
} 
echo "var $photovar={\n"; 
echo "    baseurl: \"http://" . $_SERVER["SERVER_NAME"] . dirname($_SERVER['PHP_SELF']) . "/\",\n"; 
echo "    images: [\n"; 
returnimages(); 
echo "    ],\n"; 
echo "    desc: []\n"; 
echo "}\n"; 
?>

The browser cache may need to be cleared and/or the page refreshed to see changes.

If you want more help, please include a link to the page on your site that contains the problematic code so we can check it out.

[pellsonline]

John,

Tried your suggestion with no success.

I double checked that I loaded your code correctly.

This is the link to the page on my site that I am using as a test. http://www.claragraceroman.com/album0206.htm

I ran info.php on my site and appears that EXIF is enabled for JPEG & TIFF (sensitive link removed) so I opened the three test images and saved them as JPEG.
When you look at the page you will see that the images are duplicated. One is jpg the other JPEG so I guess that doesn't matter.

I found this routine online that displays the EXIF data and the date taken is there. http://regex.info/exif.cgi

Joe

[jscheuer1]

I'm still not convinced EXIF is working on the server.

First off, the file extension (.jpg, .jpeg, .JPG, .JPEG) doesn't matter, as long as it's a JPG image.

Next - You should never link to your phpinfo() in a public forum. It's an invitation to hackers. (I've removed the link from your post for your protection)

Not being a hacker myself, it doesn't help me much other than I do know from trying this out on my WAMP server that EXIF can be enabled but not functional unless mbstring is enabled as well and that mbstring must be enabled before EXIF in the php.ini file, ex:

extension=php_mbstring.dll
extension=php_exif.dll

If possible, check the server's php.ini to make sure they appear in the correct order. From your info.php page, it looks like they might not be, as exif appears before mbstring in the Configure Command section.

As another sort of test, try this standalone page (I tried this on my WAMP server):

<!DOCTYPE html>
<html>
<head>
<title>EXIF Test</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<script type="text/javascript">
document.write(new Date('<?php
$exif = exif_read_data('http://www.claragraceroman.com/images/album0206/017.jpg');
echo date("M d, Y", $exif['FileDateTime']);
?>'));
</script>
</body>
</html>

and got:

Wed Dec 31 1969 00:00:00 GMT-0500 (Eastern Standard Time)

That means that at least that file has EXIF data including its FileDateTime property. As to whether or not your server will report it is what we are trying to determine. So host the above file on your server as - say textexif.php, and see what it gets you.

If that checks out, I have complete remake of the getpics PHP code that test out OK here using EXIF, so let me know.

[pellsonline]

John,

Did what you asked with same result (Wed Dec 31 1969 00:00:00 GMT-0500 (Eastern Standard Time))
This test picture was actually taken Aug, 6, 2013

I also tried it with an image I took this morning with same result of Dec 31, 1969

Also contacted server and ask if EXIF is configured properly but have not yet received a response.

Joe

[jscheuer1]

OK, that actually means EXIF is working, I checked another way:

<!DOCTYPE html>
<html>
<head>
<title>EXIF Test</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>

<?php
$exif = exif_read_data('http://www.claragraceroman.com/images/album0206/017.jpg');
echo $exif['FileDateTime'];
?>

</body>
</html>

I got:

0

Which (in PHP and in javascript) is that EST date. That means the EXIF FileDateTime for that file is 0. I checked the full EXIF and it is. It reports the camera as iPhone. So I guess it doesn't save that. I have a Konica Minolta that does, so I was going on that. The EXIF from that image does have an accurate value for DateTimeOriginal, but it's in a different format.

So we can do:

<!DOCTYPE html>
<html>
<head>
<title>EXIF Test</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<script type="text/javascript">
var d0 = '<?php
$exif = exif_read_data('http://www.claragraceroman.com/images/album0206/017.jpg');
echo $exif['DateTimeOriginal'];
?>'.split(/[ :]/g);
document.write(new Date(d0[0], --d0[1], d0[2], d0[3], d0[4], d0[5]));
</script>
</body>
</html>

and get:

Tue Aug 06 2013 06:47:29 GMT-0400 (Eastern Daylight Time)

Which I think is what we are after. If so this should work as the getalbumpics.php file:

<?php
Header("content-type: application/x-javascript");
function returnimages(){
    $photovar = isset($_GET['id'])? $_GET['id'] : 'galleryarray';
    if (!preg_match('#^[a-z_][a-z0-9_]+$#i', $photovar)){
        echo 'alert("id/array name must be at least two characters and contain only letters, numbers, or underscore, and cannot start with a number")';
        die();
    }
    $path = str_replace(' ', '%20', str_replace($_SERVER['DOCUMENT_ROOT'], '', str_replace('\\', '/', getcwd())));
    $base = '//' . preg_replace('#/{2,}#', '/', "{$_SERVER["SERVER_NAME"]}/$path/");
    $dirname = '.';
    $pattern = '#\.(jpg|jpeg|png|gif|bmp)$#i';
    if($handle = opendir($dirname)){
        clearstatcache();
        while(false !== ($file = readdir($handle))){
            if(preg_match($pattern, $file)){
                @$filedate = exif_read_data($file);
                if($filedate && isset($filedate['DateTimeOriginal'])){
                    $filedate = strtotime($filedate['DateTimeOriginal']);
                } else { $filedate = filemtime($file); }
                $files[$file] = $filedate;
            }
        }
        closedir($handle);
    }
    arsort($files, SORT_NUMERIC);
    $count = -1;
    foreach ($files as $file => $time){
        $jsarray[] = "[" . ++$count . ", '$file', '" . date("M d, Y", $time) . "']";
    }
    return "var $photovar = {\n\tbaseurl: '$base',\n\timages: [\n\t\t" . implode(",\n\t\t", $jsarray) . ",\n\t\t['placeholder']\n\t],\t\n\tdesc: []\n};";
}

echo returnimages();
die();
?>

BTW, as long as all of the images have this data, it already sorts the files in order from newest to oldest, so you don't have to sort them in the javascript part. But you can, it shouldn't hurt anything. But if not all of the images have that data, then those that don't will use the filetime timestamp, so will appear more recent (time of upload) in either a javascript or PHP sort.

If you don't have javascript sort the dates, you can get a little more creative in formatting them in PHP, like - "M jS, Y", which would give you dates like - Aug 6th, 2013.

The browser cache may need to be cleared and/or the page refreshed to see changes.

Note: The line:

$filedate = strtotime($filedate['DateTimeOriginal']);

or other minor parts of the PHP code might have to be expanded upon, changed or even replaced by a few lines of code for your version of PHP.

[pellsonline]

John,

I set up a test file containing five images that I know contain the date info and they display exactly as I would like.
http://claragraceroman.com/test.html

Only problem is the images don't display. I reviewed your code but can't figure it out.

Joe

[jscheuer1]

OK, that was left over from a bit of fanciness I had in that code. It's getting the wrong base URL for the images. Use this simplified version:

<?php
Header("content-type: application/x-javascript");
function returnimages(){
    $photovar = isset($_GET['id'])? $_GET['id'] : 'galleryarray';
    if (!preg_match('#^[a-z_][a-z0-9_]+$#i', $photovar)){
        echo 'alert("id/array name must be at least two characters and contain only letters, numbers, or underscore, and cannot start with a number")';
        die();
    }
    $base = "//" . $_SERVER["SERVER_NAME"] . dirname($_SERVER['PHP_SELF']) . "/";
    $dirname = '.';
    $pattern = '#\.(jpg|jpeg|png|gif|bmp)$#i';
    if($handle = opendir($dirname)){
        clearstatcache();
        while(false !== ($file = readdir($handle))){
            if(preg_match($pattern, $file)){
                @$filedate = exif_read_data($file);
                if($filedate && isset($filedate['DateTimeOriginal'])){
                    $filedate = strtotime($filedate['DateTimeOriginal']);
                } else { $filedate = filemtime($file); }
                $files[$file] = $filedate;
            }
        }
        closedir($handle);
    }
    arsort($files, SORT_NUMERIC);
    $count = -1;
    foreach ($files as $file => $time){
        $jsarray[] = "[" . ++$count . ", '$file', '" . date("M jS, Y", $time) . "']";
    }
    return "var $photovar = {\n\tbaseurl: '$base',\n\timages: [\n\t\t" . implode(",\n\t\t", $jsarray) . ",\n\t\t['placeholder']\n\t],\t\n\tdesc: []\n};";
}

echo returnimages();
die();
?>

The browser cache may need to be cleared and/or the page refreshed to see changes.

If you're interested, that other version was for a file that could get the images from any folder. It used the getcwd() function, which apparently introduces port numbers or something into the URL. I've now switched back to what was used in the original for that part.