true. but the second (third, fourth, nth) hash does not have fewer possible outcomes than the first.
Exactly.
Exactly.
Exactly.
Something else to consider: part of the reason that hashes are non-de-hash-able (or, like, whatever) is that they're lossy. Flip this bit, rotate these ones, log() that one, throw away every fifth value that is a power of two. (Random example, of course, not any real algorithm.)
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