Which parameter isn't working? I don't understand what you're trying to accomplish here.
Code:
<?php
include("include/db_conn.php");
$appid=$_REQUEST['appid'];
$pageid=$_REQUEST['pageid'];
$parentid = $_REQUEST['parentid'];
if($pageid!='') {
$query1=mysql_query("select * from page_master where page_id='".$pageid."'");
while($rows1 = mysql_fetch_array($query1))
{
$pages1 [] = array(
'pageid' => $rows1['page_id'],
'title' => $rows1['page_title'],
'type' => $rows1['page_type'],
'desc' => $rows1['description'],
'Nexturl' => $rows1['url'],
'prevurl' => '48'
);
}
$data.='<pages>';
foreach( $pages1 as $page1 )
{
$data.='<page>';
$data.='<pageid>'.$page1['pageid'].'</pageid>';
$data.='<title>'.$page1['title'].'</title>';
$data.='<type>'.$page1['type'].'</type>';
$data.='<desc>'.$page1['desc'].'</desc>';
$data.='<Nexturl>'.$page1['Nexturl'].'</Nexturl>';
$data.='<prevurl>'.$page1['prevurl'].'</prevurl>';
$data.='</page>';
}
$data.='</pages>';
$sxml=simplexml_load_string($data);
echo str_replace("\/","/",json_encode($sxml));
// Output JSON.
}
?>
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