Hi all, completely new at this and have got myself stuck!
I am trying to display a thumbnail image by connecting to my database and retrieving the URL that points to the image.
I know that the connection is working but I can't seem to get it to point to the image. Probably something really simple. Here's my code:
In my mySQL field 'thumb' contains the full URL of the image ie http://www............Code:<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Image Swap Using CSS</title> <style type="text/css"> body { margin: 0; padding: 0; background-color:#000000; } img { margin: 0; padding: 0; border: none; } .test { margin: 0; padding: 0; width: 99px; height: 130px; } .test a:hover img { visibility:hidden; } </style> </head> <body> <?php // connect to the database mysql_connect("********", "****") or die(mysql_error()); mysql_select_db("eliteescorting") or die(mysql_error()); $start=0; // expand on the searches $data=mysql_query("SELECT * FROM escorts WHERE base = 'manchester' ORDER BY RAND()"); $num_results=@mysql_num_rows($data); for($ii = $start;$ii < $num_results; $ii++){ ?> <div class="test"><a href="#"><img src="<?php echo $data[$ii]['thumb'];?>" /></a></div> <?php } ?> </body> </html>
This is just for testing, I'll get round to sorting out security issues later.
Your help will be greatly appreciated!
Regards,
Nortski.




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