Can't deal with two forms

**jangkoo** · 07-16-2010, 09:47 PM

Hi friends!
I have 1 problem with 2 forms on 1 website.
my site is here

HTML Code:

http://leejangkoo.tk/

the problem is that I can't use the form COMMENT,i mean I can't write the comment if I still enable the form chatbox
If i delete the code of chatbox, I can comment and it can display.
So what is the problem and how so solve it.
I have tried many ways in 2 days but it is still like that
the code of 2 forms are
chat box

PHP Code:


<?php

echo"<form action='chatbox.php' method='post'>";

if (!isset($_COOKIE["user"])|| $_COOKIE["user"]=="")

{

    echo "Your name";

echo "<input type='text' size=20 name='name'>";

}

echo "<textarea cols='22' rows='5' name='message'>Write here</textarea>";

echo "<input style=' background-color:#0F6' name='CHAT' type='submit' value='CHAT' />";

?>

and the comment

PHP Code:


<form action="index.php" method="post">

                    <textarea cols="60" rows="5" name="comment">Write here</textarea>

                    <br />

                    <input style=" background-color:#0F6" type="submit" name="COMMENT" value="COMMENT" />

                    </form>

is this problem with forms or with connecting to database?
the code show chat and comment are

PHP Code:


 <?php

$sql="select * from chatbox order by chat_id DESC" or die(mysql_error());

$query=mysql_query($sql);



while($row=mysql_fetch_array($query))

{

    $i++;

echo "<b style='color:#0C0;font-size:14px'>".$row["username"]."</b>   :";

echo "<font size=3>".$row["chat"]."</font>";

echo" <br />";

}

mysql_close();

?>

and

PHP Code:


 <?php

                  $result = mysql_query("select * from imgcomment") or

                    die (mysql_error());

                    $count=0;

                    while ($row = mysql_fetch_array($result))

                    if($count<10)

                    {

                        $count++;

                    echo "<br>\n";

                    echo "<font color=green size=3px>".$row["username"]."</font>";

                    echo "<font color=green size=1.5px> said</font>";

                    echo "<br>\n";

                    echo "<font color=black size=2px>".$row["comment"]."</font>";

                    echo "<br>\n";

                    }

                    mysql_free_result($result);

                    ?>

Thanks in advance.