I creating a script letting similar to forums, however Got roblems with one file:
I don't know if you understand what I mean, hovewer her you link to look it up:
http://w-luife.uphero.com/galerija/
Everything working except then you openning link, its getting not everythin is in sql..
Galerija.php
SQL file:PHP Code:<?
include('_include/dbsettings.php');
mysql_connect(host,user,pass) or die(mysql_error());
mysql_select_db(db_table);
$name = $_GET['pavadinimas'];
$take = "SELECT * FROM galerija_info WHERE pavadinimas='$name'";
$get = mysql_query($take);
$n = mysql_num_rows($get);
$i = 0;
$pavadinimas = $_GET['pavadinimas'];
echo "[ <a href='link_add.php?pavadinimas=".$pavadinimas."' > Prideti </a> ]<br />
<br />";
if($i<$n){
$pavadinimas2 = mysql_result($get,$i,'pavadinimas');
$aprasymas = mysql_result($get,$i,'aprasymas');
$photo = mysql_result($get,$i,'photo');
echo "
Cia ".$pavadinimas2.", o cia yra ".$photo." su ".$aprasymas."
";
}
$i++;
mysql_close();
?>
here to add in linkPHP Code:CREATE TABLE galerija (
id int(6) not null auto_increment,
pavadinimas varchar(250) not null,
PRIMARY KEY (id)
);
CREATE TABLE galerija_info (
id int(6) not null auto_increment,
pavadinimas varchar(250) not null,
aprasymas longtext not null,
photo longtext not null,
PRIMARY KEY (id)
);
It's confirmPHP Code:<?
include('_include/dbsettings.php');
mysql_connect(host,user,pass) or die(mysql_error());
mysql_select_db(db_table);
$pavadinimas2 = $_GET['pavadinimas'];
?>
<form action="link_conf.php" method="post">
<input type="hidden" name="pavadinimas" value="<? echo $pavadinimas2 ; ?>" /><br />
Aprasymas:<br />
<textarea name="aprasymas"></textarea>
<br />
Nuotrauka:<br />
<input type="text" name="photo" />
<br />
<br />
<input type="submit" value="Ideti" />
</form>
<?
mysql_close();
?>I want it select all things are with name pavadinimas=$pavadinimas2,PHP Code:<?
include('_include/dbsettings.php');
mysql_connect(host,user,pass) or die(mysql_error());
mysql_select_db(db_table);
$pavadinimas = $_POST['pavadinimas'];
$aprasymas = $_POST['aprasymas'];
$photo = $_POST['photo'];
$take = "INSERT galerija_info VALUES ('','$pavadinimas','$aprasymas','$photo')";
mysql_query($take);
mysql_close();
echo "Informacija sekmingai buvo ikelta i <b>".$pavadinimas."</b> skilti! <a href='galerija.php?pavadinimas=".$pavadinimas."'>Gristi</a>";
?>
but can't made it. With id I can do it, but with searching by ame not
Hope you understood




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