PHP array into javascript array

**gurmeet** · 12-27-2009, 09:02 AM

hi,
i have an array into PHP and i want to use it into javascript..
canany1 help my by guiding or giving me the coding ?
cz i want to processed that data on client,.....

plzreplysoon

**jscheuer1** · 12-27-2009, 12:04 PM

To cover all possible sorts of arrays could get complex, but this looks good for basic stuff:

http://forums.devshed.com/showpost.p...05&postcount=4

**djr33** · 12-27-2009, 05:06 PM

Use PHP to echo the data in the array as text in a javascript format.

For example:
echo 'var = ['.implode(', '$array).'];';

That's a simple array... it can certainly get more complex.

A foreach loop in php can work like this:
foreach ($array as $key=>$value) {
//do whatever you want
}

$key is the key, and $value is the value.

If it needs to be multi-layered, then you'll need a function and if statements to echo strings and start a new layer of the function for arrays.

**simplecode** · 12-30-2009, 10:14 PM

or you can use:

echo 'var = '.json_encode($array).';';

It will work also with multi-dimension arrays.

**jscheuer1** · 12-31-2009, 07:14 AM

Originally Posted by simplecode

or you can use:

echo 'var = '.json_encode($array).';';

It will work also with multi-dimension arrays.

That looks to be very useful if it does as one might imagine. However, care should be exercised:

PHP 5 >= 5.2.0, PECL json >= 1.2.0

from:

http://us2.php.net/manual/en/function.json-encode.php

**gurmeet** · 01-01-2010, 02:47 PM

Originally Posted by simplecode

or you can use:

echo 'var = '.json_encode($array).';';

It will work also with multi-dimension arrays.

its giving square breckets in output...
c this code

<?php
$arr = array ('a','b','c','d','e');

echo "var a =" . json_encode($arr)."";
?>

out put is:

var a =["a","b","c","d","e"]

but i want out put like this :
var a ={"a","b","c","d","e"}
so it can be used as array

plz give me some readymade coding for this

**jscheuer1** · 01-01-2010, 03:26 PM

This (what you say you are getting):

Code:

var a =["a","b","c","d","e"]

is a javascript array.

This:

Code:

var a ={"a","b","c","d","e"}

is a javascript error, an invalid object initializer.

Try:

PHP Code:


<script type="text/javascript">

<?php

$arr = array ('a','b','c','d','e');



echo "var a =" . json_encode($arr)."";

?>

;alert (a[1]);

</script>

or, more properly:

PHP Code:


<script type="text/javascript">

<?php

$arr = array ('a','b','c','d','e');

echo 'var a = ' . json_encode($arr) . ";\n";

?>

alert(a[1]);

</script>

Both work.

Note: Requires:

PHP 5 >= 5.2.0, PECL json >= 1.2.0

**simplecode** · 01-01-2010, 03:33 PM

Originally Posted by gurmeet

but i want out put like this :
var a ={"a","b","c","d","e"}
so it can be used as array

This give you javascript syntax error.

Try test this sample

Code:

<html>
    <script>
        <?php
        $arr1 = array ('a','b','c','d','e');
        echo "var a =" . json_encode($arr1).";";
        ?>
        alert("a: "+a[1]);
     </script>
</html>

{} brackets can be used only with associative array.

NOTE:
If you don't have PHP 5 >= 5.2.0, PECL json >= 1.2.0, or want portable code, use this

Code:

if (!function_exists('json_encode')){
    function json_encode($a){
        $str = '{';
        $dlm = '';
        if (is_array($a)){
            foreach ($a as $key => $item){
                if (is_array($item)){
                    $str.= $dlm.'"'.$key.'":'.my_json_encode($item).'';
                }else{
                    $str.= $dlm.'"'.$key.'":"'.$item.'"';
                }
                $dlm = ',';
            }
        }
        $str .= '}';
        return $str;
    }
}

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