PHP copy() function

**stu2000** · 01-19-2009, 05:56 PM

Hi there,

I'm having trouble with PHP's copy() function, and I have no idea what the solution is, any help muchly appreciated!

I'm trying to copy a .php file from one directory to another directory. However when I copy the .php file, it copies fine, BUT when I run the file, it just plain skips the PHP coding within the file, as if it's // taged out... When I copy the file through my FTP client manually, it works fine. I have NO idea why it's doing this!

Anyone have any ideas?

Thanks,

Stu

**Twey** · 01-19-2009, 06:45 PM

Make sure the execute bits are set. Is the PHP code visible if you view the page source?

**stu2000** · 01-19-2009, 07:20 PM

Hi Twey,

Thanks for your reply, I've just got a quick question:

Execute bits?

... and as for the PHP running, even a simple

PHP Code:


include 'footer.php';

line isn't running, so no footer is being shown, among other missed bits which all work fine if I upload the file through my FTP client manually.

Thanks

Stu

p.s.

Oh and also, if I re-upload the file (as I have a copy on my harddrive), and overwrite the file on the server that the PHP copy() function created, the file still doesn't work... which is odd, I'm guessing it might be some kind of permission problem? In the PHP admin file that's doing the copying, I used chmod() to change the file permission to 777 right after I copied it, if that makes any difference?

**Twey** · 01-19-2009, 08:14 PM

Of course the footer isn't being shown, but is there a <?php include 'footer.php; ?> in the page source somewhere? The surrounding <> will render it an unknown tag to the browser, so it probably won't be displayed.

**stu2000** · 01-19-2009, 08:22 PM

Hi Twey,

yeah, two of the lines within the page are

PHP Code:


<?php include 'header.php'; ?>

and

PHP Code:


<?php include 'footer.php'; ?>

But there are other calls to the database etc that are also totally ignored.

How do you mean that the surrounding <>'s will render it an unknown tag to the browser?

Thanks,

Stu

**stu2000** · 01-20-2009, 09:44 AM

When you say 'in the page source', do you mean the output that can be see by clicking 'view source'? As that's a no, the code isn't:

HTML Code:

&lt;?php include 'footer.php' ?&gt;

it's still how it should be, i.e:

PHP Code:


<?php include 'footer.php'; ?>

and instead of outputting the footer, the page source is just:

HTML Code:

<html>
<body>
</body>
</html>

Stu

**Schmoopy** · 01-20-2009, 10:44 AM

HTML Code:

&lt;?php include 'footer.php' ?&gt;

That doesn't look good, if PHP is enabled - it shouldn't be showing up in the page source, it should be completely hidden, are you sure the file is saved as .php and that your host has PHP enabled?

**stu2000** · 01-20-2009, 10:48 AM

no no, I mean the code isn't

HTML Code:

&lt;?php include 'footer.php' ?&gt;

it displays nothing in the source, and if I download the file and open it in an HTML editor, it looks fine, as in:

PHP Code:


<?php include 'footer.php' ?>

Stu

**Schmoopy** · 01-20-2009, 10:55 AM

I see, any chance you could link to the page, and are you sure PHP is enabled in the server you are using?

**stu2000** · 01-20-2009, 11:19 AM

yeah, no problem,

a couple of examples here, the first one, is the file copied by the PHP copy() function (which is now displaying absolutely nothing! I just got the background image before and nothing else):

http://www.lynchfordaquatics.co.uk/n.../testprod1.php

and this next one is the same file, I downloaded, renamed and uploaded through my FTP client:

http://www.lynchfordaquatics.co.uk/n.../testprod2.php

As you can see, this one displays everything as it should do, even though it is exactly the same file.

Thanks Schmoopy

p.s.

If the actual code of the php file would help you, let me know and I can post it for you, thanks for your help!

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