echo selectbox value and matching array item

**TheJoshMan** · 11-01-2008, 02:54 PM

Ok, so i'm technically still a virgin when it comes to PHP. I am trying to learn on my own, but I keep getting stuck on this script I'm trying to write.

Here's what I'm trying to do:

Page 1:
has a dropdown box where user can select a value
also has an array which is used to fill the select box

Page 2:
has another array of items which correspond to the Page 1 array
has processing script to handle the submitted info and match the corresponding items then echo outcome

For some reason, everytime I submit the value from the dropdown box it simply echos ALL items in the array rather than just the one that corresponds.

Here's an example (Page 1):

PHP Code:


<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
 <head>
  <title> Blah </title>
</head>
<body>
<h2>Number Matcher</h2>
<form method="post" action="script.php">
<label>Please select a number:</label>
<select name="number">
<?php
$numbers = array(0=> "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten");
for ($counter=0; $counter < sizeof($numbers); $counter++)
    {
        echo "<option>$numbers[$counter]</option>";
    }
        echo "</select>";
            for ($counter=0; $counter < sizeof($numbers); $counter++)
    {
        echo "<input type=hidden name=hidden[] value=$numbers[$counter]>";
    }
        echo "<input type=submit name=submit value=Submit></form>";
?>
</body>
</html>

And here's Page 2:

PHP Code:


<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
 <head>
  <title> Blah </title>
</head>
<body>
<?php
$digit = $_POST['number'];
$numero = array (0=> "Uno", "Dos", "Tres", "Cuatro", "Cinco", "Seis", "Siete", "Ocho", "Nueve", "Diez");
for ($counter=0; $counter < sizeof($numero); $counter++)
{
if ($hidden[$counter] == $numbers[$counter])
{
echo "The number <strong>$digit</strong> is the same as <em><strong>$numero[$counter]</strong></em> in Spanish.";
}
}
?>

</body>
</html>

And if you need a working link to see the outcome problems... then here it is too: http://www.eight7teen.com/DD/php-test/numbers.php

Also, I forgot to mention that when I test this locally on my machine... When I submit the data from the first page, it takes me to the second page and prints the entire array... (see below)

However, when I submit the data from the first page on my server... It takes me to the second page but it's completely blank. What is going on? The files are the exact same on the server as they are on my local machine!?!

**JasonDFR** · 11-01-2008, 10:49 PM

I'll look at this more later, but for starters it doesn't look like your hidden input on page one is being assigned to the $hidden variable on page two.

**Nile** · 11-02-2008, 02:17 AM

Here:

PHP Code:


<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
 <head>
  <title> Blah </title>
</head>
<body>
<h2>Number Matcher</h2>
<form method="post" action="script.php">
<label>Please select a number:</label>
<select name="number">
<?php
$numbers = array("One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten");
for ($counter=0; $counter < sizeof($numbers); $counter++)
    {
        echo "<option value='$counter'>$numbers[$counter]</option>";
    }
        echo "</select>";
        echo "<input type=submit name=submit value=Submit></form>";
?>
</body>
</html>

script.php:

PHP Code:


<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
 <head>
  <title> Blah </title>
</head>
<body>
<?php
$digit = $_POST['number'];
$numbers = array("One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten");
$numero = array ("Uno", "Dos", "Tres", "Cuatro", "Cinco", "Seis", "Siete", "Ocho", "Nueve", "Diez");
$var = "The number <strong>$numbers[$digit]</strong> is the same as <em><strong>$numero[$digit]</strong></em> in Spanish.";
echo $var;
?>

</body>
</html>

I took out your hidden field, and the for loop surrounding it. Gave the options a value of the for $counter variable. Then in script.php I put both arrays and took the for loop out, then I called the correct array by the $digit post variable.

**TheJoshMan** · 11-02-2008, 02:38 AM

thanks so much man, works like a charm!

**techietim** · 11-02-2008, 02:52 AM

If you want, you can put this all on one page so you don't have to update each page when you add new numbers. I also fixed up the HTML.

PHP Code:


<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
 <head>
  <title> Blah </title>
</head>
<body>
<h2>Number Matcher</h2>
<?php
$numbers = array('One', 'Two', 'Three', 'Four', 'Five', 'Six', 'Seven', 'Eight', 'Nine', 'Ten');
if(!isset($_POST['submit'])){
  echo '<form method="post" action="">
<label>Please select a number:</label>
<select name="number">';
  for($counter=0; $counter < sizeof($numbers); $counter++)
    echo '<option value="' . $counter . '">' . $numbers[$counter] . '</option>';
  echo '</select>
<input type="submit" name="submit" value="Submit"></form>';
}else{
  $numero = array('Uno', 'Dos', 'Tres', 'Cuatro', 'Cinco', 'Seis', 'Siete', 'Ocho', 'Nueve', 'Diez');
  $digit = $_POST['number'];
  echo 'The number <strong>' . $numbers[$digit] . '</strong> is the same as <em><strong>' . $numero[$digit] . '</strong></em> in Spanish.';
}
?>
</body>
</html>

**Nile** · 11-02-2008, 03:59 AM

Lol, I told him to do that on MSN. He got a C- on his script. (by me)

**JasonDFR** · 11-02-2008, 06:47 PM

http://www.php.net/manual/en/function.array-map.php

Check out example 3.

I stumbled across this today while looking for help on something I am doing.

Pretty funny coincidence.

Jason

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