The drop down menu now tries to position itself correctly, but since the anchor link you've defined for it is "out of place", so will the position of the drop down menu. In your source, the anchor link for the menu is defined as:
Code:
<div class="chromestyle" id="chromemenu">
<ul>
<li><a href="#" rel="dropmenu1"></a></li>
</ul>
</div>
This won't work, as you're basically defining a blank anchor link, and expecting the script to know that this anchor actually should match up with the image link somewhere above it. Instead of the above, remove it, and try something like the below instead:
Code:
<table style="width: 760px" cellspacing="0" cellpadding="0" id="chromemenu">
<tr>
<td><a href="index.htm">
<img alt="" src="nav07/home.gif" width="81" height="34" id="img1" class="style2" onMouseOut="FP_swapImgRestore()" onMouseOver="FP_swapImg(1,1,/*id*/'img1',/*url*/'nav07/homedown.gif')" /></a></td>
<td><a href="about_us.htm" rel="dropmenu1">
<img alt="" src="nav07/aboutus.gif" width="85" height="34" id="img2" class="style2" onMouseOut="FP_swapImgRestore()" onMouseOver="FP_swapImg(1,1,/*id*/'img2',/*url*/'nav07/aboutusdown.gif')" /></a></td>
<td><a href="our_bikes.htm">
<img alt="" src="nav07/ourbikes.gif" width="90" height="34" id="img3" class="style2" onMouseOut="FP_swapImgRestore()" onMouseOver="FP_swapImg(1,1,/*id*/'img3',/*url*/'nav07/ourbikesdown.gif')"></a></td>
<td>
Or if that doesn't work, what you really want is a drop down menu that can be easily associated with any link on the page, such as one of your image links. Try Anylink CSS Menu.
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