Instead of use mysql_fetch_array() use mysql_fetch_assoc(). (Could work)
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New Comer (less than 5 posts)
Instead of use mysql_fetch_array() use mysql_fetch_assoc(). (Could work)
Junior Coders
hai chriswattsuk,
first you delete the code at the starting of your program that is
<?php
/* Program: petdisplay.php
* Desc: Displays all pets in selected category.
* /
?>
<html>
<head><title>Pet Catalog</title></head>
<body>
why because
at the starting of the program we have to put the php code ,reason is some browsers do not allow the code.try it
bye
Junior Coders
remove this code at the starting of the program then you cant get such type of errors/warnings.
<?php
/* Program: petdisplay.php
* Desc: Displays all pets in selected category.
* /
?>
<html>
<head><title>Pet Catalog</title></head>
<body>
Junior Coders
Interesting because, I created a test database according to your query and I ran your code, but I get the same error in the same line...Originally Posted by medayn
I tried all I could, modifying different things, even changing the group '-STANDBY-' to just 'standby' etc...
What could be really the problem????
May be somewhere I am failing and I need to learn a lot more SQL
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