Hi,
Am very new in PHP but eager to learn. Am trying out this tutorial titled PHP News System from Video Design Core website.
Not to sure what I did wrong. Please bear with me if I am really long winded and uses layman terms.
According to the tutorial:
1.First you must create a database and enter this query - Done!
2.Make a new file called postnews.php - Done!
<body>
<?php
if (isset($addnews)):
?>
<FORM ACTION="<?php echo($PHP_SELF); ?>" METHOD=POST>
<p>Type the authors name here:<BR>
<input size="25" NAME="author">
<p>Type news title here:<BR>
<input size="25" NAME="newstitle">
<P>Type your news here:<BR>
<TEXTAREA NAME="newstext" ROWS=10 COLS=40 WRAP>
</TEXTAREA><BR>
<INPUT TYPE=SUBMIT NAME="submitnews" VALUE="SUBMIT">
</FORM>
<?php
else:
// Connect to the database
$dbcnx = @mysql_connect(
"localhost", "userID", "password");
if (!$dbcnx) {
echo( "<P>Unable to connect to the " .
"database server at this time.</P>" );
exit();
}
// the news database
if (! @mysql_select_db("news") ) {
echo( "<P>Unable to locate the news " .
"database at this time.</P>" );
exit();
}
if ("SUBMIT" == $submitnews) {
$sql = "INSERT INTO News SET " .
"NewsText='$newstext', " .
"author='$author', " .
"NewsTitle='$newstitle', " .
"NewsDate=now()";
if (mysql_query($sql)) {
echo("<P>Your news has been added.</P>");
} else {
echo("<P>Error adding submitted news: " .
mysql_error() . "</P>");
}
}
if (isset($deletenews)) {
$sql = "DELETE FROM News " .
"WHERE ID=$deletenews";
if (mysql_query($sql)) {
echo("<P>The news has been deleted.</P>");
} else {
echo("<P>Error deleting news: " .
mysql_error() . "</P>");
}
}
echo("<P> Here are all the news " .
"in our database: </P>");
$result = mysql_query(
"SELECT ID, NewsText FROM News");
if (!$result) {
echo("<P>Error performing query: " .
mysql_error() . "</P>");
exit();
}
while ( $row = mysql_fetch_array($result) ) {
$newsid = $row["ID"];
$newstext = $row["NewsText"];
echo("<P>$newstext " .
"<A HREF='$PHP_SELF?deletenews=$newsid'>" .
"Delete this News</A></P>");
}
echo("<P><A HREF='$PHP_SELF?addnews=1'>" .
"Add News!</A></P>");
endif;
?>
</body>
3. Also created another page titled news.php where the news are to be displayed - Done!
<?php
$db=mysql_connect("localhost","userID","password") or die ("cant connect");
mysql_select_db("news",$db) or die ("cant change");
$news=mysql_query("SELECT * FROM News ORDER BY NewsDate DESC LIMIT 8") or die ("cant get em");
while($rows=mysql_fetch_array($news)){
$title=$rows["NewsTitle"];
$content=$rows["NewsText"];
$date=date("F d, Y H:i ",$rows["date"]);
$author=$rows["author"];
$number="100%";
printf("<table border=1 cellspacing=0 bordercolor=000000 bgcolor=555555 style=overflow:auto>");
// the title of the news
echo "<td width=300 bgcolor=#ffffff class=first><center><b>$title</b></center></td>";
// the date
echo "<td align=right bgcolor=#ffffff class=first>$date</td><tr>";
//the news itself
echo "<td colspan=2 style=overflow:auto><i>by <A href=\"mailto:noneyet\">$author</a></i><br><center>$content</center></td></table><p>";
}
?>
</body>
However, when I test it...here's the results.
When I tried to preview the postnews.php in browser (F12), this message appeared.
Unable to locate the news database at this time.
And, when I tried to preview the news.php in browser (F12), this message appeared.
cant change
What did I do wrong?
Please advice.
Thanks so much,
JP



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