Why is my Variable Value not carrying through?

[thetestingsite]

ok, basic PHP tutorial:

when using include or require functions, if you do something like this:

include('$header');

it looks for the file name $header; however, if you do this:

include($header);

it then includes the file that is assigned to the variable $header.

Hope this helps.

[Nile]

Didn't see testingsites post.

[kuau]

Nile, I just realized that your "signature" confused me - I thought it was the answer to my question so I tried to apply it to my code -- sorry, you must have wondered what the heck I was doing.

TTS, I understand that the quotes turn it into a literal. I am just curious that the result seems to be bad syntax because when the variable is replaced, you end up with:

include(filename.php);

instead of:

include('filename.php');

I thought using the quotes around filename.php was proper syntax. But I'm not sure.
Thanks, erin