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Help with PHP code conversion to PERL
Hi!
I'm totally new to PHP and try to understand the syntax. Could anyone say what:
//Specify your URL
$URL = "http://www.exampleurl.com";
//Open a stream in READ mode
$handle = fopen ($URL, "r");
//It's this one I don't get
$key = str_replace(' ', '%20',fread($handle, 1000000));
converts into PERL? Can I rewrite this code syntax in PERL?
Thanks in advance,
/V
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