Date Issue In PHP...

[tomyknoker]

Can someone explain why this is happening... here is part of the code...

$date = date('d/m/Y');
$p = explode ( ' ', date('m Y') ); 

if ($p[0] == 1) { 
    $Month = 12; 
    $theYear = $p[1]-1; 
} 

else { 
    $Month = $p[0]-1; 
    $theYear = $p[1];
} 

if ($Month < 10) {
$theMonth = '0'.$Month;
}

else {
$theMonth = $Month;
}

$monthText = date("F", mktime(0,0,0,$theMonth+1,0,0)); 

Basically from this I am pulling info out of my database about my members, this one pulls information of them logging from last month... It works fine, but I added in the query so it says 'These members logged in $monthText'... When I ran it it was saying 'March' so I had to add the +1 after $theMonth, just not sure why I need to add the +1, any ideas?

[mwinter]

$monthText = date("F", mktime(0,0,0,$theMonth+1,0,0)); 

By specifying the date as zero (0) - an out-of-range value - the calculated date is rolled back one day into the preceding month.

If your main objective is to obtain the month as a string, I would have thought it would be computationally less expensive to use:

$monthNames = array('January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December');
$date = getdate();

$monthText = $monthNames[($date['mon'] + 10) % 12]; 

or at the very least:

$date = getDate();

$monthText = date('F', mktime(0, 0, 0, $date['mon'] - 1)); 

Mike