send value into database table using ckeckbox

[purnendu2311]

Hi all,

I have four check box, i want to send 1st & 4th value of the check box into database table after selecting one or more option. ie if i select the dating and Networking, the both should store into database. example: dating, Networking in table.
I am taking the four variable and using comma i am separting the variable. But problem is that once i am select the 1st and 4th option three comma is coming inbetween dating and friend option, but i want only one comma ie dating, Networking in table.

This is the code :::::::

<input type="checkbox" name="checkbox1" value="Dating" />Dating

<input type="checkbox" name="checkbox2" value="Serious Relationships" />Serious Relationships

<input type="checkbox" name="checkbox3" value="Friends" />Friends
<input type="checkbox" name="checkbox4" value="Networking" /> Networking


I am using this variable::::::::::;
$checkbox1=$_POST['checkbox1'];//varible for dating
$checkbox2=$_POST['checkbox2'];//varible for serious ralationship
$checkbox3=$_POST['checkbox3'];//varible for friends
$checkbox4=$_POST['checkbox4'];//varible for networking
$final=$checkbox1.",".$checkbox1.",".$checkbox1.",".$checkbox1;
$qry_ins="update register_dtl set gender='$gender',dob='$dob',occupation='$occupation',city='$city',country='$country',region='$region',postal_code='$postalcode',ethnicity='$ethnicity',bodytype= '$bodytype',height='$height',i_am_here_for='$final' where uname='".$_SESSION['username']."'";
$rs_ins=mysql_query($qry_ins) or die("error:". mysql_error());

Can anyone will help me it is urgent

Thanks & Regards

Ranjan

[codeexploiter]

Have a check like the following immediately you place values in the checkbox variables

$final = ""; //initialize this variable before starting the following condition checking
if($checkbox1 != "")
	$final = $final . $checkbox1;

if($checkbox2 != "" && $final != "")
	$final = $final .",". $checkbox2;
else
	$final = $final . $checkbox2;
	
if($checkbox3 != "" && $final != "")
	$final = $final .",". $checkbox3;
else
	$final = $final .$checkbox3;
	
if($checkbox4 != "" && $final != "")
	$final = $final .",". $checkbox4;
else
	$final = $final . $checkbox4;

After this checking store the $final in the appropriate field in your table.

Another thing RDBMS packages recommend to store atomic values in the table field in your case you are combining two values using a comma and storing it in a single field.

[purnendu2311]

Hi

Its working . Thanks for ur co-operation.

Thanks & Regards
Ranjan

[purnendu2311]

Hi

Its working fine. But afer sending the value from database, i want to select the value from databse table. My problem is that, i want the select value should be checked in the checkbox....How to do , Help me...

Example: I have inserted the dating, networking into database table. after that i want to dating, networking checkbox should be check after writing the select query.


<td align="left" valign="middle" bgcolor="#A3C5E0" class="blacktext">
<p>
<input name="checkbox1" type="checkbox" value="Dating" />
<span id="ctl00_ctl00_Main_ProfileEditContent_editBasicInfo_hereForCheckBoxList" class="items">
<label for="ctl00_ctl00_Main_ProfileEditContent_editBasicInfo_hereForCheckBoxList_0">Dating</label>
</span> </p>
<p>
<input type="checkbox" name="checkbox2" value="Serious
Relationships" />
<span id="ctl00_ctl00_Main_ProfileEditContent_editBasicInfo_hereForCheckBoxList" class="items">
<label for="ctl00_ctl00_Main_ProfileEditContent_editBasicInfo_hereForCheckBoxList_1">Serious
Relationships</label>
</span> </p>
<p>
<input type="checkbox" name="checkbox3" value="Friends" />
<span id="ctl00_ctl00_Main_ProfileEditContent_editBasicInfo_hereForCheckBoxList" class="items">Friends</span>
</p>
<p>
<input type="checkbox" name="checkbox4" value="Networking" />
Networking </p></td>




sql query::::::::::::::::::::::::




if(isset($_REQUEST['occupation']) && $_REQUEST['occupation']!="")
{
$gender=$_POST['radiobutton'];
$dob=$_POST['dob'];
$occupation=$_POST['occupation'];
$city=$_POST['city'];
$country=$_POST['country_code'];
$region=$_POST['region'];
$postalcode=$_POST['postalcode'];
$ethnicity=$_POST['ethnicity'];
$bodytype=$_POST['bodytype'];
$height=$_POST['height'];
$checkbox=$_POST['checkbox'];


$checkbox1=$_POST['checkbox1'];//varible for dating
$checkbox2=$_POST['checkbox2'];//varible for serious ralationship
$checkbox3=$_POST['checkbox3'];//varible for friends
$checkbox4=$_POST['checkbox4'];//varible for networking
//$final=$checkbox1.",".$checkbox1.",".$checkbox1.",".$checkbox1;
/*
if ($checkbox1)
{
$final= $checkbox1;
}
elseif($checkbox1 && $checkbox2 )
{
$final= $checkbox1.",".$checkbox2;
}
elseif($checkbox1 && $checkbox2 )
{


}
*/
$final = ""; //initialize this variable before starting the following condition checking
if($checkbox1 != "")
$final = $final . $checkbox1;

if($checkbox2 != "" && $final != "")
$final = $final .",". $checkbox2;
else
$final = $final . $checkbox2;

if($checkbox3 != "" && $final != "")
$final = $final .",". $checkbox3;
else
$final = $final .$checkbox3;

if($checkbox4 != "" && $final != "")
$final = $final .",". $checkbox4;
else
$final = $final . $checkbox4;

$qry_ins="update register_dtl set gender='$gender',dob='$dob',occupation='$occupation',city='$city',country='$country',region='$region',postal_code='$postalcode',ethnicity='$ethnicity',bodytype= '$bodytype',height='$height',i_am_here_for='$final' where uname='".$_SESSION['username']."'";
$rs_ins=mysql_query($qry_ins) or die("error:". mysql_error());

}


Thanks & regards

Ranjan