Try this (example only, you will have to edit the variables in the php section of the code):
Code:
<?php
$conn = mysql_connect("server","username","password");
mysql_select_db("database", $conn);
$imgs = mysql_query("SELECT * FROM `table`");
if (mysql_num_rows($imgs) > 0) {
?>
<table border="0" cellpadding="0">
<caption><strong>Air Show Photos</strong></caption>
<tr>
<td width="100%"><img src="plane1.gif" width="300" height="240" name="photoslider"></td>
</tr>
<tr>
<td width="100%"><form method="POST" name="rotater">
<div align="center"><center><p><script language="JavaScript1.1">
var photos=new Array()
var which=0
/*Change the below variables to reference your own images. You may have as many images in the slider as you wish*/
<?php
$i = 0;
while ($row = mysql_fetch_array($imgs)) {
echo 'photos['.$i.']="'.$row["image"].'";
$i++;
}
?>
function backward(){
if (which>0){
window.status=''
which--
document.images.photoslider.src=photos[which]
}
}
function forward(){
if (which<photos.length-1){
which++
document.images.photoslider.src=photos[which]
}
else window.status='End of gallery'
}
</script><input type="button" value="<<Back" name="B2"
onClick="backward()"> <input type="button" value="Next>>" name="B1"
onClick="forward()"><br>
<a href="#" onClick="which=1;backward();return false"><small>Start Over</small></a></p>
</center></div>
</form>
</td>
</tr>
</table>
<p align="center"><font face="arial" size="-2">This free script provided by</font><br>
<font face="arial, helvetica" size="-2"><a href="http://javascriptkit.com">JavaScript
Kit</a></font></p>
<?php
}
?>
Not tested, but should work. Hope this helps
Bookmarks