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Thread: Right to left... instead of left to right - Perplexed

  1. #1
    Join Date
    Mar 2007
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    Default Right to left... instead of left to right - Perplexed

    Hello,

    There are 2 files in the archive attached. I am trying to use a DD DHTML script for moving an object across the screen.
    The only problem is I need from right to left, this script is left to right......... and I know almost nothing about tweaking javascript.

    If you open the page in the archive, you will see what I mean.

    I also tried to email the author of the little script... dead email address.

    Trying to get images to go right to left... instead of left to right.
    example in my original post... plus I tried tweaking it myself to no avail.

    Could anyone assist me with the tweak?

    Code is below.



    <script language="JavaScript1.2">

    //Flying planes - by John Ely
    //Modified from: Autumn leaves script- by Kurt Grigg (kurt.grigg@virgin.net)
    //Modified by Dynamic Drive for NS6 functionality
    //visit http://www.dynamicdrive.com for this script

    //Pre-load your image below!
    //CHANGE 5 to the number of images listed below
    grphcs=new Array(5)

    //PRELOAD the involved images (extend or contract variables according to # of images used)
    Image0=new Image();
    Image0.src=grphcs[0]="crow.gif"
    Image1=new Image();
    Image1.src=grphcs[1]="crow.gif"
    Image2=new Image();
    Image2.src=grphcs[2]="crow.gif"
    Image3=new Image();
    Image3.src=grphcs[3]="crow.gif"
    Image4=new Image();
    Image4.src=grphcs[4]="crow.gif"

    //SPECIFY number of images to randomly display concurrently from list above. Less the more efficient
    Amount=3;
    Ypos=new Array();
    Xpos=new Array();
    Speed=new Array();
    Step=new Array();
    Cstep=new Array();
    ns=(document.layers)?1:0;
    ns6=(document.getElementById&&!document.all)?1:0;
    ie=document.all

    if (ns){
    for (i = 0; i < Amount; i++){
    var P=Math.floor(Math.random()*grphcs.length);
    rndPic=grphcs[P];
    document.write("<LAYER NAME='sn"+i+"' LEFT=0 TOP=0><img src="+rndPic+"></LAYER>");
    }
    }
    else{
    document.write('<div style="position:absolute;top:0px;left:0px"><div style="position:relative">');
    for (i = 0; i < Amount; i++){
    var P=Math.floor(Math.random()*grphcs.length);
    rndPic=grphcs[P];
    document.write('<img id="si'+i+'" src="'+rndPic+'" style="position:absolute;top:0px;left:0px">');
    }
    document.write('</div></div>');
    }
    WinHeight=(ns||ns6)?window.innerHeight-70:window.document.body.clientHeight;
    WinWidth=(ns||ns6)?window.innerWidth:window.document.body.clientWidth;
    for (i=0; i < Amount; i++){
    Ypos[i] = Math.round(Math.random()*WinHeight);
    Xpos[i] = Math.round(Math.random()*WinWidth);
    Speed[i]= Math.random()*5+1;
    Cstep[i]=0;
    Step[i]=Math.random()*0.1+0.05;
    }
    function fly(){
    var WinHeight=(ns||ns6)?window.innerHeight:window.document.body.clientHeight;
    var WinWidth=(ns||ns6)?window.innerWidth-70:window.document.body.clientWidth;
    var hscrll=(ns||ns6)?window.pageYOffset:document.body.scrollTop;
    var wscrll=(ns||ns6)?window.pageXOffset:document.body.scrollLeft;

    for (i=0; i < Amount; i++){
    sy = Speed[i]*Math.sin(Cstep[i]);
    sx = Speed[i]*2;
    Ypos[i]+=sy;
    Xpos[i]+=sx;
    if (Xpos[i] > WinWidth){
    Ypos[i]=Math.round(Math.random()*WinHeight);
    Xpos[i]=-60;
    Speed[i]=Math.random()*5+1;
    }

    if (ns){
    document.layers['sn'+i].left=Xpos[i]+wscrll;
    document.layers['sn'+i].top=Ypos[i];
    }

    else if (ns6){
    document.getElementById("si"+i).style.left=Xpos[i]+wscrll;
    document.getElementById("si"+i).style.top=Math.min(WinHeight,Ypos[i]);
    }

    else{
    eval("document.all.si"+i).style.left=Xpos[i]+wscrll;
    eval("document.all.si"+i).style.top=Ypos[i];
    }
    Cstep[i]+=Step[i];
    }
    setTimeout('fly()',20);
    }

    if (ie||ns||ns6)
    window.onload=fly
    //-->
    </script>

    Thanks

    Tony

  2. #2
    Join Date
    Mar 2007
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    Default

    An answer was provided for me in another forum.

    Kind Regards,

    Tony

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