Login Code Error

**Titan85** · 09-12-2006, 11:07 AM

hey, i have been working on getting a login script working, but always get an error. Here is my code:

PHP Code:


<?php

if (($_POST['username']=="")) {

    echo"
    <html>
    <title>Login Page</title>
    <body>
    Please fill out the form below to acces that page
    <form method=\"post\" action=\"process.php\">
    Username: <input type=\"text\" name=\"username\" />
    <br />
    Password: <input type=\"text\" name=\"password\" />
    <br />
    <input type=\"button\" value=\"Submit\" />
    </form>
    </body>
    </html>";
    
} else {
    $username = $_POST['username'];
    $passowrd = $_POST['password'];
        session_start();    
    if ($username == "kyle" && $password == "price") {
        $permission == "yes"
    
    $username = $_POST['username'];
    session_register("permission");   
    session_register("username"); 
    
    if ($permission == "yes") {
    
        echo"
        <html>
        <title>Login Page</title>
        <body>
        You are now logged in, feel free to navigate the protected pages
        <br />
        <a href=\"page1.html\">Page 1</a>
        <br />
        <a href=\"page2.html\">Page 2</a>
        </body>
        </html>";
    } else {
    echo "The username or password you entered was incorrect, please retry.";
    }
?>

the error i get is this "Parse error: syntax error, unexpected T_VARIABLE in /home/echodesi/public_html/testing/login/test1.php on line 27"

I would appreciate any help

**codeexploiter** · 09-12-2006, 11:32 AM

I've modified your code on certain locations now it works correctly. Plz compare your code with mine to find the difference

PHP Code:


<?php



if ($_POST['username'] == "") 

{



    echo "<html><title>Login Page</title><body>Please fill out the form below to acces that page<form method=\"post\" action=\"process.php\">sername: <input type=\"text\" name=\"username\" /><br />Password: <input type=\"text\" name=\"password\" /><br /><input type=\"submit\" value=\"Submit\" /></form></body></html>";

    

} 

else 

{

    $username = $_POST['username'];

    $password = $_POST['password'];



    echo "$username";

    echo "$password<br>";

    

    

    session_start();    

    

    if ($username == "kyle" && $password == "price")

    {

        

        $permission = "yes";

        

        $username = $_POST['username'];

        

        session_register("permission");   

        

        session_register("username"); 

        

        echo "$permission<br>";

        

        

        if ($permission == "yes") 

        {

    

                echo"<html><title>Login Page</title><body>You are now logged in, feel free to navigate the protected pages<br /><a href=\"page1.html\">Page 1</a><br /><a href=\"page2.html\">Page 2</a></body></html>";

        }

        else 

        {

            echo "The username or password you entered was incorrect, please retry.";

        }

    }

}

?>

Plz note that according to your code the file name must be process.php
--------------------------------------------------------------------------
Problems in your code

1.

Posted by Titan85

PHP Code:


$permission == "yes"

This is an assignment operation you missed two things:

(a) You need only single = for assigning a value

(b) You missed the ; in that line

2. The {} used in the nested if statement are not ordered some mismatch were there. I've corrected it.

3. In your form section you used button instead of submit button.

**Titan85** · 09-12-2006, 04:04 PM

thanks a lot codeex, got it all working after fixing the errors you pointed out. However, i did run into some other errors. I am new to this so I do not know what his means error is telling me:
"Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /home/echodesi/public_html/testing/login/process.php:24) in /home/echodesi/public_html/testing/login/process.php on line 28

Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/echodesi/public_html/testing/login/process.php:24) in /home/echodesi/public_html/testing/login/process.php on line 28".

I know it has something to do with the code on line 28 which is my session_start(); area. What I did was i actually named the code i gave before "process.php" and then used another page called "login.html" to login. Here is the code for login.html incase you need it:

Code:

<html>
<title>Login Page</title>
<body>
Please fill out the form below to login.
<form method="post" action="process.php">
Username: <input type="text" name="username" />
<br />
Password: <input type="text" name="password" />
<br />
<input type="submit" value="Submit" />
</form>
</body>
</html>

Thanks again

**ItsMeOnly** · 09-12-2006, 05:02 PM

it means you tried to send cookie and "pragma: no-cache" header after part of HTML content was sent to client (process.php, line 24- I suspect that's "echoing" of username and password, remove it): the cookie needs to be sent BEFORE anything on page (like HTML with nested PHP code).

BTW, I see you're using nested html code in PHP, you can use alternate PHP syntax to enclose "unescaped" html content:

Code:

<?php if ($_POST['username'] == "") : ?>
I'm an unescaped HTML with all the ""'s and ''s
<?php else : ?>
I'm another html content with unescaped ""s and ''s, <?php=$variable?> me
<?php endif ?>

**Titan85** · 09-12-2006, 05:19 PM

Originally Posted by ItsMeOnly

it means you tried to send cookie and "pragma: no-cache" header after part of HTML content was sent to client (process.php, line 24- I suspect that's "echoing" of username and password, remove it): the cookie needs to be sent BEFORE anything on page (like HTML with nested PHP code).

BTW, I see you're using nested html code in PHP, you can use alternate PHP syntax to enclose "unescaped" html content:

Code:

<?php if ($_POST['username'] == "") : ?>
I'm an unescaped HTML with all the ""'s and ''s
<?php else : ?>
I'm another html content with unescaped ""s and ''s, <?php=$variable?> me
<?php endif ?>

Thanks man, I did that and it worked out great

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