New Comer (less than 5 posts)
onLoad function didn't work on Firefox
I have external javascript scripts
In file php named list.php in body tagCode:function window_close(id){ window.open("logout2.php?id="+id,"Logout","width=470,heigth=340"); }
In IE when i close the window (click x ) the code work. But in mozilla firefox it didn't work.Code:<body onUnload="window_close('<? echo $_GET["id"] ;?>')">
Why?
One more question can javascript detect browser's back button click or not click?
Elite Coders
If the user is closing the browser or leaving your site, you should consider it too late to do anything. You want to have the user do something, make a point of telling them. In any case, you'll still need to handle a user that doesn't log out (or whatever).Originally Posted by novarli
You may be able to remind the user:
but once they're going, it's too late to expect the browser to do anything.Code:this.onbeforeunload = function() { if (notReadyToLeave) { return 'You haven't saved your work!'; } };
A pop-up blocker could prevent what you're attempting, so you're off to a bad start as it is, but I ask you: Why not? If the user has instructed the browser to close, why should it reopen a connection and make another request to the server? Why should it disobey the user and stay open?In IE when i close the window (click x ) the code work. But in mozilla firefox it didn't work.
Why?
The unload (and beforeunload) event fires for many reasons; you can't determine which applies.One more question can javascript detect browser's back button click or not click?
Mike
New Comer (less than 5 posts)
After i checked it in firefox was work, but in single window. Not in tab.
Is the event this.onbeforeunload can be applied in tab window?
Elite Coders
It works fine here, though support may be version-dependent. Also note that there are some browsers where it won't work at all; this is only an aid to users, nothing more.
To invoke the prompt, return a string (including an empty one). To bypass it, return undefined (either allow the function to drop out without encountering a return statement, or use "return;").
Mike
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