Verifying if a source has a script

[Twey]

except 1 thing.. for <script is that for javascript?

Yes. You never specified what sort of script you were talking about, so I naturally assumed the most obvious one.

and would i be able to change that?

Unlikely. Server-side scripts are very different from client-side scripts from the point of view of the client (which is what the PHP script would be acting as); you'd need to devise an entirely different method, if it were possible at all.

[blm126]

<?php
$affiliate = 'somesite.com'; //Don't add anyhting that isn't ALWAYS in the URL
if(strpos(strtolower($_SERVER['HTTP_REFERER']),$affiliate) !== false){
echo 'Welcome Affiliate';
}
else{
echo 'Welcome Guest';
}
?>

This should work for both #1 #2 as long as you change somesite.com to the opposite;

[Twey]

strpos(strtolower(

What's wrong with stripos()?

Relying on HTTP_REFERER (except as a convenience) is dangerous, since a lot of firewalls strip it.

[blm126]

What's wrong with stripos()?

The large number of PHP 4 servers

Relying on HTTP_REFERER (except as a convenience) is dangerous, since a lot of firewalls strip it.

As long as it is not mission critical I don't see why HTTP_REFERER should not be used. If it has to be one hundred percent accurate then the get variable method I posted a couple posts ago should be used.

[Twey]

Ah, so 'tis.

[cursed]

Thanks..

is it possible to only do it once?

Because i want a script that also includes to another website, and that same script that checks another website.

and if this wont stop, then it would be an endless loop.