_.-*>another Problem!<*-._

**jr_yeo** · 07-09-2006, 12:36 AM

Code:

<? @chmod("requests.php", 0777);
  if(!is_writable("requests.php")){
    @chmod("requestline.php", 0777); 
    if(!is_writable("requestline.php")){

// somewhere else on the script

    } 
  }

please don't take this the wrong way but, do u have any background/training at all with any programming language available in the market like ( i dunno) Turbo Pascal, Turbo C, C++, Java, JavaScript, VB.NET, C#, J# to name a few

i just would like to assess what are ur strengths and weaknesses in regards to understanding code snippets and programming jargons.

**jad9321** · 07-09-2006, 12:52 AM

Nope only Html and Php...

Can you guys look at this:

Code:

<?
$dbhost = "DBHOST";
$dbuser = "DBUSER";
$dbpwd = "DBPASSWORD";
$dbname = "DBNAME";
mysql_connect($dbhost, $dbuser, $dbpwd);
mysql_select_db($dbname);
?>
<html>
<head>
<title>Request Line</title>
</head>
<body>
<?php
if (!isset($_POST['submit'])) {
?>
<form action="" method="post">
Habbo Name: <input type="text" name="Habbo Name"><br>
Song Request: <input type="text" name="Snog Request"><br>
Shoutout/Joke: <input type="text" name="Shoutout/Joke"><br>
<input type="submit" name="submit" value="Request">
</form>
<?php
$Habbo Name = $_POST['Habbo Name'];
$Song Request = $_POST['Song Request'];
$Shoutout/Joke = $_POST['Shoutout/Joke'];
mysql_query("INSERT INTO `request` (Habbo Name, Song Request, Shoutout/Joke) VALUES ('$Habbo Name', '$Habbo Name', '$Shoutout/Joke')");{
echo "Your Request has ben sent!
?>
</body>
</html></body>
</html>

I seem to be getting this error:

Parse error: parse error, unexpected T_STRING in /fpgs/fpgshttpd/smileyoureahabbo/scripts/radiobox/requestline.php on line 24

**jr_yeo** · 07-09-2006, 01:16 AM

Nope only Html and Php...

tnx for that info.

Code:

if(condition)
  sun is up;
else
  raining;

in this case, there is no need for open and close curly brace { }

but

Code:

if (condition) {
   sun is up;
   joe will play outside;
} else {
   raining;
   joe will play inside;
}

in this case, there should be a corresponding closing curly brace for every open curly brace that exists in the script.

NOW, to the heart of the matter

Like Twey said

Originally Posted by Twey

It's a rather unhelpful error, I must admit. Newer versions of PHP are more descriptive.

What it's trying to tell you is that the page has ended while there's still a code block open.

**Twey** · 07-09-2006, 01:21 AM

The latest problem:

Code:

mysql_query("INSERT INTO `request` (Habbo Name, Song Request, Shoutout/Joke) VALUES ('$Habbo Name', '$Habbo Name', '$Shoutout/Joke')");{
echo "Your Request has ben sent!";

The red brace shouldn't be there but is, and the blue quote and semicolon should be there but aren't

Code:

</body>
</html></body>
</html>

Conversant with HTML, eh?

**jad9321** · 07-09-2006, 02:31 AM

Still gets error... (on latest problem)

**Twey** · 07-09-2006, 11:23 AM

Oh, and the variable names are totally ridiculous.

A variable name may contain only alphanumeric characters and underscores, can't start with a number, and must always be prefixed with a dollar sign ($).

**BLiZZaRD** · 07-09-2006, 11:42 AM

Unless the variable name is in a string...

PHP Code:


<?php
$array['456'];
$array['-'];
>?


<?php ${'456'} = "my number variable"; ?>

Would then work just the same...

Complex I know.. but at least I am learning some of this stuff

**jad9321** · 07-09-2006, 03:44 PM

Ok... That didn't even fix it...
Heres the script now:

Code:

<?
$dbhost = "DBHOST";
$dbuser = "DBUSER";
$dbpwd = "DBPASSWORD";
$dbname = "DBNAME";
mysql_connect($dbhost, $dbuser, $dbpwd);
mysql_select_db($dbname);
?>
<html>
<head>
<title>Request Line</title>
</head>
<body>
<?php
if (!isset($_POST['submit']));{
?>
<form action="" method="post">
Habbo Name: <input type="text" name="Habbo Name"><br>
Song Request: <input type="text" name="Snog Request"><br>
Shoutout/Joke: <input type="text" name="Shoutout/Joke"><br>
<input type="submit" name="submit" value="Request">
</form>
<?php
$HabboName = $_POST['Habbo Name'];
$SongRequest = $_POST['Song Request'];
$ShoutoutJoke = $_POST['Shoutout/Joke'];
mysql_query("INSERT INTO `request` (Habbo Name, Song Request, Shoutout/Joke) VALUES ('$HabboName', '$SongRequest', '$ShoutoutJoke')");{
echo "Your Request has ben sent!";
?>
</body>
</html></body>

I get error:

Parse error: parse error, unexpected $ in /fpgs/fpgshttpd/smileyoureahabbo/scripts/radiobox/requestline.php on line 32

**Twey** · 07-09-2006, 03:50 PM

You still haven't removed that opening brace I told you to.

**jad9321** · 07-09-2006, 03:55 PM

Which One?

Thread: _.->another Problem!<-._

Thread Tools

Search Thread

Bookmarks

Bookmarks

Posting Permissions

Thread: _.-*>another Problem!<*-._

Thread Tools

Search Thread

Bookmarks

Bookmarks

Posting Permissions

Thread: _.->another Problem!<-._