how to find a character in a variable

Hi James,
I'm not sure I understand what you are tryring to do, but finding a character in a string can be easily done with the help of the substring() method.

Hey James,
Just to add the easiest way to find if a character is present in a string is String.indexOf(); https://developer.mozilla.org/en-US/...String/indexOf
E.g.

Code:

---

let exampleString = "This is a string with a backslash \\";

//This evaluates to true as there is a backslash.
if(exampleString.indexOf("\\") > -1)
{
       
}

---

For your specific question I'm also not sure what you're asking exactly.

Thank you. I will try out your suggestions.

I think that both of your examples have pointed me in the right direction. If it works I will post the solution. The script I am working on updating is a simple gallery script with a few buttons that allows my to cycle through images.

Here is one of the examples listed on the PHP page for strpos. What I am/was looking for is the javascript equivalent of that.

PHP Code:

---

<?php
$mystring = 'abc';
$findme   = 'a';
$pos = strpos($mystring, $findme);

// The !== operator can also be used.  Using != would not work as expected
// because the position of 'a' is 0. The statement (0 != false) evaluates 
// to false.
if ($pos !== false) {
     echo "The string '$findme' was found in the string '$mystring'";
         echo " and exists at position $pos";
} else {
     echo "The string '$findme' was not found in the string '$mystring'";
}
?>

---

Got it. I replaced

Code:

---

function newio(n){
newio.Num += n || -newio.Num;
newio.Num = newio.Num < 0? newio.count - 1 : newio.Num % newio.count;
newio.imgo.src = '/images/screenshots/' + newio.ar[newio.Num];
newio.output.value = newio.ar[newio.Num];
return false;
}

---

with

Code:

---

function newio(n){
newio.Num += n || -newio.Num;
newio.Num = newio.Num < 0? newio.count - 1 : newio.Num % newio.count;
var n=newio.ar[newio.Num];
var n = n.search("/");
if (n<0)
{
newio.imgo.src = '/images/screenshots/' + newio.ar[newio.Num];
}
else
{
newio.imgo.src=newio.ar[newio.Num];
}
newio.output.value = newio.ar[newio.Num];
return false;
}

---