how can i solve following thing

PHP Code:

---

<?php
$toppost = mysql_query("SELECT * FROM `page` ORDER BY `page`.`id` DESC limit 0,3");
if(mysql_num_rows($toppost)>0){
        
    echo '<div id="list_home">';
    while($showpost = mysql_fetch_assoc($toppost)){
        $fromDB     = $showpost['page_content'];
        $show = substr($fromDB,0,100);
        //$receive = wordwrap($fromDB,110,"<!----Cut---->");
//        $pieces = explode("<!----Cut---->", $receive);
        echo '<div class="travel">
<h3> '.$showpost['page_name'].'  </h3>
<p> '.$show.' </p>
<a href="pages/view/'.$showpost['page_url'].'"> Lees meer <span> >> </span> </a>
</div>';
    }
    echo '</div>';
}
?>

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I want to show the picture if there is one in the beginning of the article . ( also when it is a remote banner) it must be recaled.

Then i also want to show 15 titles in 3 koloms with 5 links. I managed to show 3 titles based on this script but the 25 are to far from eachoter.