Parse error: syntax error unexpected 'echo'

This error pops for the following line:

PHP Code:

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<?php if(isset ($error)) (echo '<div id="login-errors">'.$error.'</div>'); ?>

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EDIT

If I change "echo" to "print" it returnes no errors, but then it messes up the page layout and prints the following in the upper left corner:

PHP Code:

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array (size=3)
    'username' => string 'dfdf' (length=4)
    'password' => string 'dfdfd' (length=5)
    'logintoadmincenter' => string 'Login' (length=5) 


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However, it does do somewhat, what it should be doing which is "print" 'Invalid Credentials' in the DIV.

PHP Code:

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 <?php if(isset ($error)) {
      echo '<div id="login-errors">'.$error.'</div>'
} ?>

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Use {} for if statements, rather than (). And don't end that with a ;. I'm not exactly sure what's not working there, but the code was written incorrectly, and it should now work.

Quote:

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Originally Posted by djr33

PHP Code:

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 <?php if(isset ($error)) {
      echo '<div id="login-errors">'.$error.'</div>'
} ?>

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Use {} for if statements, rather than (). And don't end that with a ;. I'm not exactly sure what's not working there, but the code was written incorrectly, and it should now work.

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That creates a new error:

Parse error: syntax error, unexpected '}', expecting ',' or ';'

Here is what I have written incase I did it wrong:

PHP Code:

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<?php if(isset ($error)) { echo '<div id="login errors">'.$error.'</div>' } ?>

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Alright I added ";" at the end and it fixed it, but now the page is breaking layout and displaying:

PHP Code:

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array (size=3) 
    'username' => string 'dfdf' (length=4) 
    'password' => string 'dfdfd' (length=5) 
    'logintoadmincenter' => string 'Login' (length=5) 


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So why is this PHP breaking my HTML layout and adding that code in the upper left corner which is not what it is suppose to do:

My PHP

PHP Code:

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<?php
    session_start();
    if($_POST && isset($_POST['logintoadmincenter'])) 
    {
        include_once '/include/connection.php';
        
        $username = $_POST['username'];
        $password = $_POST['password'];
        
        if (empty($username) && empty($password)) 
        {
            
            $error = "Please fill in the required fields";
        }
        else 
        {
            print "<pre>";
            var_dump($_POST);
            $username = strip_tags ($username);
            $password = strip_tags ($password);
            
            $username = mysql_real_escape_string ($username);
            $password = mysql_real_escape_string ($password);
            $password = md5($password);
            $sql = mysql_query("SELECT * From Members WHERE name = '$username' && password = '$password' LIMIT 1") or die (mysql_error ());
            $num_rows = mysql_num_rows ($sql);
            if ($num_rows == 1)
            {
                $rows = mysql_fetch_array($sql);
                extract ($rows);
                
                $_SESSION['username'] = $name;
                $_SESSION['level'] = $access_level;
                
                if (isset ($$_SESSION['username']));
                {
                    $update = msql_query("UPDATE Members SET last_log_time = now()") or die(mysql_error());
                    
                    header("location: index.php");
                }
            }
            else
            {
                $error = 'Invalid Credentials';
            }
        }
    }
?>

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Never mind I found the issue:

PHP Code:

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print "<pre>";
            var_dump($_POST); 


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Quote:

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Alright I added ";" at the end and it fixed it,

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Oops, I missed that.