Making PHP insert code in the same page with the html code...

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06-01-2009, 11:37 AM
heavensgate15

Making PHP insert code in the same page with the html code...

hey, I want to know whether it's possible to write your PHP insert code together with your HTML code where your forms are created...... what I mean is something like this:

Code:

<?php //code for inserting the data found in the forms from the html code below ?> <html> <head> <title> Inserting data from forms to the database</title> </head> <body> <form action="nextpage.php" method="POST"> //input tags </form> </body> </html>

You know, I tried this one but when I checked out my database after executing this, nothing has been added to my database... But I saw some of my classmates having this kind of codes... I've already asked them, but they cannot explain to me why... I feel like, this kind of code will not work if I'm the one who's gonna write it... please help... T_T
06-01-2009, 11:50 AM
Nile

You can only do that once the user presses the submit button, take some look in the links below:
http://www.google.com/search?hl=en&r...in+php&spell=1
06-01-2009, 12:38 PM
heavensgate15

ahw... I looked all the links that you gave... I didn't find something that could answer my question....
06-01-2009, 03:59 PM
traq

if you're asking how to write both the form and the form processing code on the same page, try this:

PHP Code:

<?php if (!isset($_POST['submit'])) { //if form is not submitted, echo '<input type="submit" name="submit" value="submit">'; //show the form. } else { //otherwise, //php code to process form goes here } ?>
06-01-2009, 04:34 PM
forum_amnesiac

Likewise you can do this, in a php file, when you have retrieved the data you want.

PHP Code:

<? PHP code here that creates a variable $php_variable ?> <html> ...... <input type="text" value='<? echo "$php_variable"?>'><? echo "php_variable" ?> ...... </html>
06-02-2009, 01:24 PM
heavensgate15

thanks for the reply.. but I want to know how my code above is executed... what will happen if my php code for inserting data from forms is placed above my html code? Is my php code for inserting data is executed then after the user clicks the submit button? or it is not? What would be the case if I put it after my html code? Is the result would be the same?
06-02-2009, 02:55 PM
forum_amnesiac

It doesn't matter where you put the PHP in relation to the HTML, the PHP will always execute first.

That is why in your HTML form you have method="POST" and action="someaction.php", this way your HTML can get the field variables that PHP can then process.
06-03-2009, 01:05 AM
traq

However, if you use the "if - else" method I posted above, then it is actually the php code that is writing the html. So, the php will choose to either write the form OR process the submission, based on whether or not the form has been submitted already - but it won't do both.

It might be easier for you to think of the two steps not as two parts of the same script, but as two different scripts that do different parts of the job. The form and the code to process the form could easily be on separate pages.
06-03-2009, 05:04 PM
heavensgate15

hmm... I understand what you mean... But still, there are lots of question in my mind... hmm, let's put it like this... I have a simple php scripts:

Code:

simple.php <?php include('dbconnect.php'); $name = $_POST[name]; $age = $_POST[age]; $data = "insert into simplerecord values(null,'$name','$age')"; mysql_query($data) or die(mysql_error()); ?> <html> <head> <title> simple form </title> </head> <body> <form action="simple2.php" method="POST"> <p><strong>Name:</strong><br> <input type="text" name="name"></p> <p><strong>Age:</strong><br> <input type="text" maxlength="2" name="age"></p> <p><input type="submit" value="send"></p> </form> </body> </html>

Code:

simple2.php <?php include('dbconnect.php'); $data = "select * from simplerecord"; $query = mysql_query($data); $num = mysql_num_rows($query); $x = 0; while($x < $num) { $name = mysql_result($query,$x,"name"); $ID = mysql_result($query,$x,"ID"); $age = mysql_result($query,$x,"age"); printf("Name: %s<br>",$name); printf("ID: %d<br>",$ID); printf("Age: %d<br><br>",$age); $x++; } ?>

Code:

dbconnect.php <?php $con = mysql_connect("localhost","root","") or die(mysql_error()); mysql_select_db("db",$con); ?>

let's say, these 3 scripts create an application...These are the things that I found out.... First is the simple.php... In this script, when I didn't put a value on the action attribute, the process seems to be ok, I successfully added a record (simple2.php is not yet created)... so the form tag looks like this:

Code:

<form action="" method="POST">

When I created the simple2.php, the form tag in simple.php script looks like this:

Code:

<form action="simple2.php" method="POST">

But this time, when I test it through my browser(filling up the name and age) and checked my database, the record that I inserted become null in my database (the attributes name and age has no value in my database but the attribute ID has a value)... Why is that?

OUTPUT in browser when simple2.php was not yet created: // I put display code in the same page

Name: lourence john cabaluna
ID: 1
Age: 18

Attributes values in the database when simple2.php was not yet created:

ID = 1
name = lourence john cabaluna
age = 18

OUTPUT in browser when simple2.php was created:

Name: lourence john cabaluna
ID: 1
Age: 18

Name:
ID: 2
Age: 0

Attributes values in the database when simple2.php was created:

ID = 1
name = lourence john cabaluna
age = 18

ID = 2
name =
age = 0
06-07-2009, 10:37 AM
heavensgate15

kindly help me about this.. it's still bugging me....

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