Heh. I saw that when he finally put it in PHP tags, but at that point I thought it was just a typo he made when posting the code. :D
To avoid problems like that in the future, I would recomend that you get a syntax highlighter like PHP Eclipse. (Actually, PHP eclipse is a full IDE, not just a syntax highlighter.)
I'm thinking that's the problem, it has to be a problem with that line... otherwise the way he has it set up it would have die()d a long time agoQuote:
Originally Posted by allahverdi
motormichael12, solved already ^^. Look at page 2 :)
I'm happy that i could help to you :D
Oh lol didn't notice there were other pages, sorry :O
Anyway I am using that same function and had the error just yesterday and come on today to see someone else get it... weird :O
Now if all you php/mysql scripting support could redirect your attention to my topic xD
If you want paste your code here and say the error. I think we can help you...
Already made a topic earlier: http://www.dynamicdrive.com/forums/s...ad.php?t=33994
I HAVE THIS ERROR..
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in c:\program files\easyphp1-8\www\e-exam\proses_hapus2_group.php on line 13
THIS MY CODING
<?php
session_start();
include 'dbase.php';
$group=$_GET['group'];
session_register("group");
$_SESSION["group"]=$group;
//echo $_SESSION["id"]; exit;
$sql=mysql_query("SELECT * FROM kumpulan WHERE group = '$group'");
$record=mysql_fetch_array($sql, MYSQL_ASSOC);
?>
<p> </p>
<form name="form1" method="post" action="hapus_pasti_group.php">
<p align="center" class="style1" style="font-weight: bold">ANDA PASTI UNTUK PADAM MAKLUMAT INI? </p>
<p class="style1"> </p>
<table width="89" height="53" border="1" align="center">
<tr>
<td width="79" height="23" bgcolor="#990099"><div align="center" style="font-size: 14px; color: #FFFFFF"><span style="font-weight: bold">KOD PROGRAM </span></div></td>
</tr>
<tr>
<td height="22"><?php echo $record["group"];?></td>
</tr>
</table>
<div align="center"></div>
<p align="center" class="style1">
<label>
<input name="btn_hapus" type="submit" id="btn_hapus" value="PADAM" onclick "return pasti()"/>
</label>
</p>
<p align="right"><strong> MEDAYN SYSTEM </strong></p>
<p><a href="delete_program.php"><img src="image/Set-02c-june.gif" width="58" height="40" border="0"></a></p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
</form>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
<p> </p>
ANYBODY CAN HELP ME
Try splitting the above code into two lines.. Also try echoing your query itself to know what exactly it looks likeCode:$sql=mysql_query("SELECT * FROM kumpulan WHERE group = '$group'");
Code:$query = "SELECT * FROM kumpulan WHERE group = '$group'";
\\You can comment out the below line for later; Now use it just for testing
echo $query;
$sql=mysql_query($query);
after i try wif ur coding..
im also hav a problem..
SELECT * FROM kumpulan WHERE group = '-STANDBY-'
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in c:\program files\easyphp1-8\www\e-exam\proses_hapus2_group.php on line 19
hai chriswattsuck
Please remove this code .if you want to put the html code after the php with out using <html><head><body> tags u can directly use the <tabl> <tr>..tags at any where.
at the begining of the page you should write php code only.try this.
<?php
/* Program: petdisplay.php
* Desc: Displays all pets in selected category.
* /
?>
<html>
<head><title>Pet Catalog</title></head>
<body>
Thanks & Regards
anu