PHP+file handling+confused???

Twey, it gives a Parse error: parse error, unexpected $ in /var/www/html/shachi/php/test/testup.php on line 38

Twey: Are you around??

Any help here??

Any Help Here???

Whoops, typo. Try this one:

Code:

---

<?php
define('DATABASE_FILE', 'database_fake.php');
define('SEPARATOR', ',');
define('LINEBREAK', "\n");

define('USERNAME', 0);
define('PASSWORD', 1);
define('EMAIL', 2);
define('COUNTRY', 3);
define('ZIP', 4);

function updateUser() {
  $ret = 0;
  $lines = array_unique([url=http://www.php.net/file]file[/file](DATABASE_FILE));
  $argv = func_get_args();
  $conditions = array();
  $changes = array();
  for($i = 0; $i < count($argv) && $argv[$i] != SEPARATOR; $i += 2)
    $conditions[$argv[$i]] = $argv[$i + 1];
  for(++$i; $i < count($argv); $i += 2)
    $changes[$argv[$i]] = $argv[$i + 1];
  for($i = 0; $i < count($lines); ++$i) {
    $cline = explode(SEPARATOR, $lines[$i]);
    $changeThisLine = false;
    foreach($conditions as $k => $v)
      if($changeThisLine = ($cline[$k] == $v)) continue;
    foreach($changes as $k => $v)
      $cline[$k] = $v;
    ++$ret;
  }
  $f = fopen(DATABASE_FILE, 'w');
  fwrite($f, str_replace(LINEBREAK . LINEBREAK, LINEBREAK, implode("\n", $lines)));
  fclose($f);
  return $ret;
}
updateUser(USERNAME, 'Shachi', COUNTRY, 'nepal', SEPARATOR, COUNTRY, 'Nepal', EMAIL, 'some.new@email-address.com');
?>

---

Twey, It didn't work.:(

But I tried to update the code from liro from the other post and came up with something like this:

(For test purposes used online.txt with | as separator the original database will have ,)

Code:

---

<?php
function replaceLine($f, $etsi, $first, $second) {
if(!file_exists($f)) {
        die("Sorry the file " . $f . " could not be found.");
    } else {
    $filearr = file($f);
    $sisalto;

        for($i = 0; $i < count($filearr); $i++) {
            list($id, $nimi, $passu) = explode("|", $filearr[$i]);
if($first == ""){
$first = $nimi;
}
if($second == ""){
$second = $passu;
}
            if($id == $etsi) {
                $sisalto .= $id . "|" . $first . "|" . $second . "\n";
            } else {
                $sisalto .= $filearr[$i];
            }
        }
        $fi = fopen($f, "w");
        fwrite($fi, $sisalto);
        fclose($fi);
    }
}
replaceLine("online.txt", "Test7", "", "");
?>

---

But it has a problem that if the values are not supplied it replaces the second and third values with the second and third values of the first line. I need a function to loop through every line of the array searching for a key and then give the index number of the array. So far I have made something like this:

Code:

---

<?php
$loopIndex = 0;
$test = array('Test0','Test1','Test2','Test3');
#$test = file("online.txt");
while($test[$loopIndex] != "Test4|test5|test6" && $loopIndex < 4){
$loopIndex++;
}
if($loopIndex < 4){
echo "Found supplied value at index ".$loopIndex;
}
#echo $test[3];
?>

---

online.txt looks something like this:

Code:

---

Test1|test2|test3
Test4|test5|test6
Test7|test8|test9
Test10|test11|test12

---

But as soon as I uncomment the $test = file("online.txt"); it shows nothing.
I have tried my best but could not come up with a suitable code. I have almost lost.

Any ideas??

Quote:

---

Twey, It didn't work.

---

You ought to know by now not to say "it didn't work." :) What went wrong?

Oops!! Sorry. It doesn't update the file. I have been trying to fix it but unforutnately I don't have much brain about PHP. :(

This is tested:

Code:

---

<?php
define('DATABASE_FILE', 'database_fake.php');
define('SEPARATOR', ',');
define('LINEBREAK', "\n");

define('USERNAME', 0);
define('PASSWORD', 1);
define('EMAIL', 2);
define('COUNTRY', 3);
define('ZIP', 4);

function updateUser() {
  $ret = 0;
  $lines = array_unique(file(DATABASE_FILE));
  $argv = func_get_args();
  $conditions = array();
  $changes = array();
  for($i = 0; $i < count($argv) && $argv[$i] !== SEPARATOR; $i += 2)
    $conditions[$argv[$i]] = $argv[$i + 1];
  for(++$i; $i < count($argv); $i += 2)
    $changes[$argv[$i]] = $argv[$i + 1];
  for($i = 0; $i < count($lines); ++$i) {
    $cline = explode(SEPARATOR, $lines[$i]);
    $changeThisLine = false;
    foreach($conditions as $k => $v)
      if(!($changeThisLine = ($cline[$k] == $v))) break;
    foreach($changes as $k => $v)
      $cline[$k] = $v;
    $lines[$i] = implode(SEPARATOR, $cline);
    ++$ret;
  }
  $f = fopen(DATABASE_FILE, 'w');
  fwrite($f, str_replace(LINEBREAK . LINEBREAK, LINEBREAK, implode("\n", $lines)));
  fclose($f);
  return $ret;
}
updateUser(USERNAME, 'Shachi', COUNTRY, 'nepal', SEPARATOR, COUNTRY, 'NePaL', EMAIL, 'some.new@email-address.com');
?>

---

It works, but not with the line of PHP code in the file. You should remove it.

Twey, it edits all the user's information. For example if the database_fake.php is like this:

Code:

---

Test,test,test@test.com,sweden
testuser,test,test@user.com,uk

---

Then after executing the PHP script it changes the values to :

Code:

---

Test,test,some.new@email-address.com,NePaL
testuser,test,some.new@email-address.com,NePaL

---

And by the way if I remove the <?php exit()?> lines then anyone would be able to view the database(sure I could encrypt the password with md5 hash but what about the email addresses??They'd be a great source for spambots).

I am sorry to make you write bunch of codes and take up your time but I need help and I cannot do it myself. You are more experienced than me.