_.->another Problem!<-._

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07-09-2006, 12:36 AM
jr_yeo

Code:

<? @chmod("requests.php", 0777); if(!is_writable("requests.php")){ @chmod("requestline.php", 0777); if(!is_writable("requestline.php")){ // somewhere else on the script } }

please don't take this the wrong way but, do u have any background/training at all with any programming language available in the market like ( i dunno) Turbo Pascal, Turbo C, C++, Java, JavaScript, VB.NET, C#, J# to name a few :p

i just would like to assess what are ur strengths and weaknesses in regards to understanding code snippets and programming jargons. :D
07-09-2006, 12:52 AM
jad9321

Nope only Html and Php...

Can you guys look at this:

Code:

<? $dbhost = "DBHOST"; $dbuser = "DBUSER"; $dbpwd = "DBPASSWORD"; $dbname = "DBNAME"; mysql_connect($dbhost, $dbuser, $dbpwd); mysql_select_db($dbname); ?> <html> <head> <title>Request Line</title> </head> <body> <?php if (!isset($_POST['submit'])) { ?> <form action="" method="post"> Habbo Name: <input type="text" name="Habbo Name"><br> Song Request: <input type="text" name="Snog Request"><br> Shoutout/Joke: <input type="text" name="Shoutout/Joke"><br> <input type="submit" name="submit" value="Request"> </form> <?php $Habbo Name = $_POST['Habbo Name']; $Song Request = $_POST['Song Request']; $Shoutout/Joke = $_POST['Shoutout/Joke']; mysql_query("INSERT INTO `request` (Habbo Name, Song Request, Shoutout/Joke) VALUES ('$Habbo Name', '$Habbo Name', '$Shoutout/Joke')");{ echo "Your Request has ben sent! ?> </body> </html></body> </html>

I seem to be getting this error:

Parse error: parse error, unexpected T_STRING in /fpgs/fpgshttpd/smileyoureahabbo/scripts/radiobox/requestline.php on line 24
07-09-2006, 01:16 AM
jr_yeo

Quote:

Nope only Html and Php...

tnx for that info.

Code:

if(condition) sun is up; else raining;

in this case, there is no need for open and close curly brace { }

but

Code:

if (condition) { sun is up; joe will play outside; } else { raining; joe will play inside; }

in this case, there should be a corresponding closing curly brace for every open curly brace that exists in the script.

NOW, to the heart of the matter :D
Like Twey said

Quote:

Originally Posted by Twey

It's a rather unhelpful error, I must admit. Newer versions of PHP are more descriptive.

What it's trying to tell you is that the page has ended while there's still a code block open.
07-09-2006, 01:21 AM
Twey

The latest problem:

Code:

mysql_query("INSERT INTO `request` (Habbo Name, Song Request, Shoutout/Joke) VALUES ('$Habbo Name', '$Habbo Name', '$Shoutout/Joke')");{ echo "Your Request has ben sent!";

The red brace shouldn't be there but is, and the blue quote and semicolon should be there but aren't :)

Code:

</body> </html></body> </html>

Conversant with HTML, eh? :p
07-09-2006, 02:31 AM
jad9321

Still gets error... (on latest problem)
07-09-2006, 11:23 AM
Twey

Oh, and the variable names are totally ridiculous.

A variable name may contain only alphanumeric characters and underscores, can't start with a number, and must always be prefixed with a dollar sign ($).
07-09-2006, 11:42 AM
BLiZZaRD

Unless the variable name is in a string...

PHP Code:

<?php $array['456']; $array['-']; >? <?php ${'456'} = "my number variable"; ?>

Would then work just the same...

Complex I know.. but at least I am learning some of this stuff :p
07-09-2006, 03:44 PM
jad9321

Ok... That didn't even fix it...
Heres the script now:

Code:

<? $dbhost = "DBHOST"; $dbuser = "DBUSER"; $dbpwd = "DBPASSWORD"; $dbname = "DBNAME"; mysql_connect($dbhost, $dbuser, $dbpwd); mysql_select_db($dbname); ?> <html> <head> <title>Request Line</title> </head> <body> <?php if (!isset($_POST['submit']));{ ?> <form action="" method="post"> Habbo Name: <input type="text" name="Habbo Name"><br> Song Request: <input type="text" name="Snog Request"><br> Shoutout/Joke: <input type="text" name="Shoutout/Joke"><br> <input type="submit" name="submit" value="Request"> </form> <?php $HabboName = $_POST['Habbo Name']; $SongRequest = $_POST['Song Request']; $ShoutoutJoke = $_POST['Shoutout/Joke']; mysql_query("INSERT INTO `request` (Habbo Name, Song Request, Shoutout/Joke) VALUES ('$HabboName', '$SongRequest', '$ShoutoutJoke')");{ echo "Your Request has ben sent!"; ?> </body> </html></body>

I get error:

Parse error: parse error, unexpected $ in /fpgs/fpgshttpd/smileyoureahabbo/scripts/radiobox/requestline.php on line 32
07-09-2006, 03:50 PM
Twey

You still haven't removed that opening brace I told you to.
07-09-2006, 03:55 PM
jad9321

Which One?

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