What is the best way to loop through an array?

[kuau]

I have created a table (using css) to display 3 different levels of pricing. The price level depends on what time of year it is. The 3 column headings display the data ranges for which the prices apply. There can be more than one date range for a given price level as shown below:

agency car_from car_until rate_table
Avis 2009-08-16 2009-12-15 1
Avis 2009-01-01 2009-06-14 1
Avis 2009-06-15 2009-08-15 2
Avis 2009-12-15 2009-12-31 3

I have the prices displaying properly but am having trouble displaying the date ranges in the column headings. It places the 2nd date range for the 1st column in the 2nd column, which is price level 2. Here is my attempt at code:


$sql = "SELECT * FROM dates WHERE `agency` = '".$agency."' AND rate_table > 0 ORDER BY rate_table";
$result1 = mysql_query($sql,$connection) or die("Couldn't execute $sql query.";

$i=0;
while ($row = mysql_fetch_array($result1)) {
$i++;
$car_from[$i] = $row['car_from'];
$car_until[$i] = $row['car_until'];

$daterange[1] = $car_from[1]." - ".$car_until[1]."<br>";
$daterange[2] = $car_from[2]." - ".$car_until[2]."<br>";
$daterange[3] = $car_from[3]." - ".$car_until[3]."<br>";
}

the html to display the headings

<div class="tablehead">Effective Dates<br><?php echo $daterange[1]; ?></div>
<div class="tablehead">Effective Dates<br><?php echo $daterange[2]; ?></div>
<div class="tablehead">Effective Dates<br><?php echo $daterange[3]; ?></div>

This is what it looks like: http://www.carrentalhawaii.com/html/rates3.php
How do I tell it to put 2 date ranges in column one instead of moving it to column 2?
I never did quite grasp the use of [$i]. Thanks.

[forum_amnesiac]

Would this work for you


$sql = "SELECT * FROM dates WHERE `agency` = '".$agency."' AND rate_table > 0 ORDER BY rate_table";
$result1 = mysql_query($sql,$connection) or die("Couldn't execute $sql query.";
$i=0;
$daterange[1]="":
$daterange[2]="":
$daterange[3]="":

while ($row = mysql_fetch_array($result1)) {
$i++;
$car_from[$i] = $row['car_from'];
$car_until[$i] = $row['car_until'];

if ($row['rate_table']==1){
$daterange[1] = $daterange[1].$car_from[1]." - ".$car_until[1]."<br>";
}
if ($row['rate_table']==2){
$daterange[2] = $daterange[2].$car_from[2]." - ".$car_until[2]."<br>";
}
if ($row['rate_table']==3){
$daterange[3] = $daterange[3].$car_from[3]." - ".$car_until[3]."<br>";
}
}

I think it should put all the dates with the same rates into the same heading

[kuau]

Dear amnesiac: Thanks a million for helping me!! It now works perfectly.

So that you can learn from this too, I have put the results of the above code here:

http://www.carrentalhawaii.com/html/rates3.php

As you can see, it is an improvement, but repeats the first date in column one and still puts the date in column 2 instead. However, your code enabled me to fix it by making a few minor changes, but to be honest, I do not understand why yours doesn't work, or why mine does. I would love to understand it if someone can please explain. Here is what worked (I changed the numbers to $i):


if ($row['rate_table']==1){
$daterange[1] = $daterange[1].$car_from[$i]." - ".$car_until[$i]."<br>";
}
if ($row['rate_table']==2){
$daterange[2] = $daterange[2].$car_from[$i]." - ".$car_until[$i]."<br>";
}
if ($row['rate_table']==3){
$daterange[3] = $daterange[3].$car_from[$i]." - ".$car_until[$i]."<br>";
}

and what it looks like working correctly:

http://www.carrentalhawaii.com/html/rates.html

I couldn't have done this without you and now I can get on to the next thing.

Mahalo plenty! e :)