queerfm
04-25-2009, 12:51 PM
Hi I am trying to give every user there own access key however some users are getting the same random numbers of other users
Here is my code if someone can help that would be nice
//random number
function generate_cust_ID()
{
srand ((double)microtime()*1000000000);
$number=rand(1,9999999999);
return $number;
}
if (!isset($cust_ID))
{
$cust_ID=generate_cust_ID($number);
}
$accesskey = $cust_ID;
$result = @mysql_query("SELECT usid FROM accesscode WHERE usid= '$usid'");
if(!$result || !mysql_num_rows($result))
{
$query2="INSERT INTO accesscode (usid,date,rand) VALUES ('$usid','$MyTimeStamp','$accesskey')";
$results=mysql_query($query2) OR DIE("Your SQL: " . $query2 . "<br/> Produced this Error: " . mysql_error());
if (mysql_affected_rows() == 1) {
echo "<center><font='black'>Access On Facebook<BR/>Your access code is:<br/></font>";
}
$query = "SELECT * FROM accesscode WHERE usid = '$usid'";
$result = mysql_query($query);
$num = mysql_fetch_array($result);
$rand = $num[rand];
print $rand;
echo"<br/><a href='http://apps.new.facebook.com/' target='_blank'>Go To Application</a>";
echo "</center>";
}
else {
$query = "SELECT * FROM accesscode WHERE usid = '$usid'";
$result = mysql_query($query);
$num = mysql_fetch_array($result);
$rand = $num[rand];
echo "<center><font='black'>Access On Facebook<BR/>Your access code is:<br/></font>";
print $rand;
echo"<br/><a href='http://apps.new.facebook.com/' target='_blank'>Go To Application</a>";
echo "</center>";
}
Here is my code if someone can help that would be nice
//random number
function generate_cust_ID()
{
srand ((double)microtime()*1000000000);
$number=rand(1,9999999999);
return $number;
}
if (!isset($cust_ID))
{
$cust_ID=generate_cust_ID($number);
}
$accesskey = $cust_ID;
$result = @mysql_query("SELECT usid FROM accesscode WHERE usid= '$usid'");
if(!$result || !mysql_num_rows($result))
{
$query2="INSERT INTO accesscode (usid,date,rand) VALUES ('$usid','$MyTimeStamp','$accesskey')";
$results=mysql_query($query2) OR DIE("Your SQL: " . $query2 . "<br/> Produced this Error: " . mysql_error());
if (mysql_affected_rows() == 1) {
echo "<center><font='black'>Access On Facebook<BR/>Your access code is:<br/></font>";
}
$query = "SELECT * FROM accesscode WHERE usid = '$usid'";
$result = mysql_query($query);
$num = mysql_fetch_array($result);
$rand = $num[rand];
print $rand;
echo"<br/><a href='http://apps.new.facebook.com/' target='_blank'>Go To Application</a>";
echo "</center>";
}
else {
$query = "SELECT * FROM accesscode WHERE usid = '$usid'";
$result = mysql_query($query);
$num = mysql_fetch_array($result);
$rand = $num[rand];
echo "<center><font='black'>Access On Facebook<BR/>Your access code is:<br/></font>";
print $rand;
echo"<br/><a href='http://apps.new.facebook.com/' target='_blank'>Go To Application</a>";
echo "</center>";
}