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Raw Dog
01-31-2009, 04:01 AM
1) Script Title: Drop Down Menu Copying

2) Script URL (on DD): http://www.dynamicdrive.com/dynamicindex1/dropdowncontrol.htm

3) Describe problem:

I am using this code for my website. However, I have multiple links, which means more drop down menus. Now I am trying to get the the second link the have the menu.

http://khmediatest.freehostia.com

As you can see, the first link works, but the second doesn't. I have the CSS already duplicated, but I need something else duplicated to be done. Do I need to upload a new dropdownmenu.js file and set it as _2?


// Copyright (C) 2005-2008 Ilya S. Lyubinskiy. All rights reserved.
// Technical support: http://www.php-development.ru/
//
// YOU MAY NOT
// (1) Remove or modify this copyright notice.
// (2) Re-distribute this code or any part of it.
// Instead, you may link to the homepage of this code:
// http://www.php-development.ru/javascripts/dropdown.php
//
// YOU MAY
// (1) Use this code on your website.
// (2) Use this code as part of another product.
//
// NO WARRANTY
// This code is provided "as is" without warranty of any kind.
// You expressly acknowledge and agree that use of this code is at your own risk.


// ***** Popup Control *********************************************************

// ***** at_show_aux *****

function at_show_aux(parent, child)
{
var p = document.getElementById(parent);
var c = document.getElementById(child );

var top = (c["at_position"] == "y") ? p.offsetHeight+2 : 0;
var left = (c["at_position"] == "x") ? p.offsetWidth +2 : 0;

for (; p; p = p.offsetParent)
{
top += p.offsetTop;
left += p.offsetLeft;
}

c.style.position = "absolute";
c.style.top = top +'px';
c.style.left = left+'px';
c.style.visibility = "visible";
}

// ***** at_show *****

function at_show()
{
var p = document.getElementById(this["at_parent"]);
var c = document.getElementById(this["at_child" ]);

at_show_aux(p.id, c.id);
clearTimeout(c["at_timeout"]);
}

// ***** at_hide *****

function at_hide()
{
var p = document.getElementById(this["at_parent"]);
var c = document.getElementById(this["at_child" ]);

c["at_timeout"] = setTimeout("document.getElementById('"+c.id+"').style.visibility = 'hidden'", 333);
}

// ***** at_click *****

function at_click()
{
var p = document.getElementById(this["at_parent"]);
var c = document.getElementById(this["at_child" ]);

if (c.style.visibility != "visible") at_show_aux(p.id, c.id); else c.style.visibility = "hidden";
return false;
}

// ***** at_attach *****

// PARAMETERS:
// parent - id of the parent html element
// child - id of the child html element that should be droped down
// showtype - "click" = drop down child html element on mouse click
// "hover" = drop down child html element on mouse over
// position - "x" = display the child html element to the right
// "y" = display the child html element below
// cursor - omit to use default cursor or specify CSS cursor name

function at_attach(parent, child, showtype, position, cursor)
{
var p = document.getElementById(parent);
var c = document.getElementById(child);

p["at_parent"] = p.id;
c["at_parent"] = p.id;
p["at_child"] = c.id;
c["at_child"] = c.id;
p["at_position"] = position;
c["at_position"] = position;

c.style.position = "absolute";
c.style.visibility = "hidden";

if (cursor != undefined) p.style.cursor = cursor;

switch (showtype)
{
case "click":
p.onclick = at_click;
p.onmouseout = at_hide;
c.onmouseover = at_show;
c.onmouseout = at_hide;
break;
case "hover":
p.onmouseover = at_show;
p.onmouseout = at_hide;
c.onmouseover = at_show;
c.onmouseout = at_hide;
break;
}
}

hamiltonian
02-02-2009, 03:45 PM
You don't need multiple js files. Just make sure your DIV ID's are unique (parent1, parent2, child1, child2 etc.) and when you call at_attach(parent, child, showtype, position, cursor) you pass the differnt parent and child id's. If you have CSS formating based on DIV ID's you will have to create a class for your formatting and add that to your ID's.

Good Luck!