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bluewalrus
11-03-2008, 04:32 PM
I'm trying to make this accept multiple inputs but its only working with one right now. I added 2 more input fields but it ignores them. Any ideas? Thanks for looking and any suggestion.


<?php
//define a maxim size for the uploaded images in Kb
define ("MAX_SIZE","9000000");

//This function reads the extension of the file. It is used to determine if the file is an image by checking the extension.
function getExtension($str) {
$i = strrpos($str,".");
if (!$i) { return ""; }
$l = strlen($str) - $i;
$ext = substr($str,$i+1,$l);
return $ext;
}

//This variable is used as a flag. The value is initialized with 0 (meaning no error found)
//and it will be changed to 1 if an errro occures.
//If the error occures the file will not be uploaded.
$errors=0;
//checks if the form has been submitted
if(isset($_POST['Submit']))
{
//reads the name of the file the user submitted for uploading
$image=$_FILES['image']['name'];
//if it is not empty
if ($image)
{
//get the original name of the file from the clients machine
$filename = stripslashes($_FILES['image']['name']);
//get the extension of the file in a lower case format
$extension = getExtension($filename);
$extension = strtolower($extension);
//if it is not a known extension, we will suppose it is an error and will not upload the file,
//otherwise we will do more tests
if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))
{
//print error message
echo '<h1>Unknown extension!</h1>';
$errors=1;
}
else
{
//get the size of the image in bytes
//$_FILES['image']['tmp_name'] is the temporary filename of the file
//in which the uploaded file was stored on the server
$size=filesize($_FILES['image']['tmp_name']);

//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
{
echo '<h1>You have exceeded the size limit!</h1>';
$errors=1;
}

//we will give an unique name, for example the time in unix time format
$image_name=$image;
//the new name will be containing the full path where will be stored (images folder)
$newname="images/".$image_name;
//we verify if the image has been uploaded, and print error instead
$copied = copy($_FILES['image']['tmp_name'], $newname);
if (!$copied)
{
echo '<h1>Copy unsuccessfull!</h1>';
$errors=1;
}}}}

//If no errors registred, print the success message
if(isset($_POST['Submit']) && !$errors)
{
echo "<h1>File Uploaded Successfully! Upload Another?</h1>";
}
?>
<!--next comes the form, you must set the enctype to "multipart/frm-data" and use an input type "file" -->
<form name="newad" method="post" enctype="multipart/form-data" action="">
<table>
<tr><td><input type="file" name="image"></td></tr>
<tr><td><input type="file" name="image"></td></tr>
<tr><td><input type="file" name="image"></td></tr>
<tr><td><input name="Submit" type="submit" value="Upload image"></td></tr>
</table>
</form>

Jesdisciple
11-03-2008, 07:21 PM
Change each input to this:
<input type="file" name="image[]">Then access them as an array:
for($i = 0; $i < count($_FILES['image']); $i++){
$image = $_FILES['image'][$i];
//Handle $image.
}or
foreach($_FILES['image'] as $image){
//Handle $image.
}

bluewalrus
11-03-2008, 07:36 PM
oo ok thanks so the [] automatically keeps track of how many there are?

and i end the for at the end of the code for 1 image right?

Jesdisciple
11-03-2008, 08:20 PM
Yes. [] is a PHP construct; see Arrays (http://www.php.net/manual/en/language.types.array.php#language.types.array.syntax.modifying).

But I don't understand your second question... EDIT: Oh, yes: You only handle one image at a time inside the loop.