View Full Version : making this a link

12-02-2006, 07:36 AM
I'm trying to make this line a link can anyone help I tried a view different ways but with no luck lol just kept getting a blank page

print $category['catalogname']."(".checkQuan($category['catalogid']).")<br />";

12-02-2006, 02:27 PM
A link to where?

12-02-2006, 07:46 PM
don't really understand the questions cause some info is missing in your original post. But it looks like you should add something like
<a href="[URL HERE]">[HYPERLINK TEXT HERE]</a> to your code.


12-02-2006, 07:51 PM
I'm assuming you want something like this:

print '<a href="URL">'.$category['catalogname'].'('.checkQuan($category["catalogid"]).')"></a><br />';

but there is info missing in your original post. Please post more info so we can help out more.

EDIT: Sorry, was typing up post, got sidetracked, and clicked post reply without going back and looking at the thread for new posters, GT.